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lawyer [7]
3 years ago
5

The figure is made up of a cylinder, a cone, and a half sphere. The radius of the half sphere is 3 inches. What is the volume of

the composite figure? Use 3.14 for Pi. Round to the nearest hundredth. A cylinder, half sphere, and cone. The radius for all figures is 3 inches. The height of the cylinder is 6 inches and height of the cone is 4 inches. Recall the formulas V = B h V = one-third B h and V = four-thirds pi r cubed
Mathematics
2 answers:
wolverine [178]3 years ago
7 0

The volume of the composite figure is 263.76 inches³

Step-by-step explanation:

The volume of a cylinder of radius r and height h is

  • V = πr²h ⇒ Bh

The volume of a cone of radius r and height h is

  • V = \frac{1}{3} πr²h ⇒ \frac{1}{3} Bh

The volume of a sphere with radius r is

  • V = \frac{4}{3} πr³

∵ The figure is made up of a cylinder, a cone, and a half sphere

∵ The radius of the cylinder = 3 inches

∵ The height of the cylinder = 6 inches

∵ π = 3.14

- Use the rule of the volume of the cylinder above

∴ The volume of the cylinder = (3.14)(3)²(6)

∴ The volume of the cylinder = 169.56 inches³

∵ The radius of the cone = 3 inches

∵ The height of the cone = 4 inches

∵ π = 3.14

- Use the rule of the volume of the cone above

∴ The volume of the cone = \frac{1}{3}(3.14)(3)^{2}(4)

∴ The volume of the cone = 37.68 inches³

∵ The radius of the half sphere = 3 inches

∵ π = 3.14

- Use the rule of the volume of the sphere above to find the

   volume of the half sphere

∴ The volume of half sphere = (\frac{1}{2})(\frac{4}{3})(3.14)(3)^{3}

∴ The volume of half sphere = 56.52 inches³

To find the volume of the composite figure add the volumes of the three shapes above

∵ The volume of the composite figure = 169.56 + 37.68 + 56.52

∴ The volume of the composite figure = 263.76 inches³

The volume of the composite figure is 263.76 inches³

Learn more:

You can learn more about the volume in brainly.com/question/12497249

#LearnwithBrainly

Igoryamba3 years ago
5 0

Answer:

263.76 inches³

Step-by-step explanation:

just did on EDG 2020

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What are the x and y intercepts of f(x) = x2-x-12/x2+5x+6 and is there a hole? ​
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Step-by-step explanation:

Given  f ( x ) =2 x ^2 − 18/x^2-16

find all asymptotes, holes and intercepts.

Factor the numerator and denominator.

f ( x ) =2 ( x ^2 − 9 )/( x + 4 ) ( x − 4 )

f ( x ) =2 ( x +3 ) ( x − 3 )/( x + 4 ) ( x − 4 )

A hole exists when the numerator and denominator contain the same factor (a factor "cancels out"). This function has no holes.

To find the vertical asymptote(s) (VA), find the values of  x

which make the denominator equal zero. The function is undefined at these values of  x

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Set each factor of the denominator equal to zero and solve.

x + 4 = 0  and x − 4 = 0

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These are the VAs.

To find the horizontal asymptote(HA), compare the degree of the numerator and denominator. If the degrees are the same, the HA is the ratio of the leading coefficients.

For  f ( x) =2 x ^2 − 18/x^2-16

the degree in both numerator and denominator is  2

and the ratio of the leading coefficients is 2/1=1

The HA is  x = 2

The  x  intercept is the value at which the function (or "y") equals zero. If the numerator is zero, the function equals zero.

2 ( x + 3 ) ( x − 3 ) = 0

x + 3 = 0    x − 3 = 0

x = − 3   and  x = − 3

The  x  intercepts are  ( − 3 , 0 )  and  ( 3 , 0 ) .

The  y  intercepts are found by setting  x = 0 .

f ( 0 ) = 2 ( 0 ) ^2 − 18/( 0 )^2 − 16 = 9 /8

The  y  intercept is  ( 0 , 9/ 8 ) .

graph{(2x^2-18)/(x^2-16) [-10.04, 9.96, -3.56, 6.44]}

HOPE THIS HELPS YOU!!!!

        =)

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3 years ago
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