Find the equation of a line given the point and slope (1,3) m=3

1 answer:

8 0

Simple....

we know the formula you need to use is y=mx+b....

plug 'n chug....

3=3(1)+b

3=3+b
-3 -3
b=0

Thus.....y=3x

Thus, your answer.

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Find the area of the triangle enclosed by these lines with the following vertices. y = x, x = 0, y = 5 (0,0), (0,5), (5,5)

Lina20 [59]

The are of the triangle will be 12.5 units.

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lesantik [10]

Answer: Option 'A' is correct.

Step-by-step explanation:

Since we have given that

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$a\times (b+c+d)=a\times b+a\times c+a\times d$

According to option'A', we get that

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d = 0.08

So, it becomes,

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3 years ago

Which graph represents the solution to the system of inequalities below?

Reika [66]

Answer:

The correct option is;

Step-by-step explanation:

The given system of inequalities are;

5·x - 4·y > 4...(1)

x + y < 2...(2)

Representing both inequalities as a function of "y", gives;

For, 5·x - 4·y > 4...(1), we have;

-4·y > 4 - 5·x

y < 4/(-4) - 5·x/(-4)

∴ y < 5·x/4 - 1

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y < 2 - x

Therefore, y is less than the values given by the equation of the straight line equalities, and the feasible region is given by the common region under both dashed lines representing both inequalities as shown in the attached diagram created using Microsoft Excel

The correct option is therefore, B.