Let's represent the numbers by : x, x+1, x+2, x+3
x+x+1+x+2+x+3=40 The third number in the sequence is x+2
4x+6=40 8.5+2=10.5
4x+6-6=40-6 Therefore the third number in the sequence is
4x=34 10.5
4x/4=34/4
x=8.5
Yes, 104.12 is greater than 104.02.
Reason: if you subtract 3 on both sides of the equal sign that will leave you with 7.
