Answer: Approximately 6.3876 years
When rounding to the nearest whole number, this rounds up to 7 years.
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Work Shown:
We'll use the compound interest formula
A = P*(1+r/n)^(n*t)
where,
- A = amount of money after t years
- P = initial deposit amount or principal
- r = interest rate in decimal form
- n = compounding frequency
- t = number of years
In this case, we know that,
- A = 2P, since we want the initial amount to double. P can be any positive real number you want and it doesn't affect the answer.
- r = 0.11
- n = 4, since we're compounding 4 times a year
- t = unknown, what we want to solve for
So,
A = P*(1+r/n)^(n*t)
2P = P*(1+r/n)^(n*t)
2 = (1+r/n)^(n*t)
2 = (1+0.11/4)^(4*t)
2 = 1.0275^(4t)
Ln(2) = Ln(1.0275^(4t))
Ln(2) = 4t*Ln(1.0275)
4t*Ln(1.0275) = Ln(2)
t = Ln(2)/(4*Ln(1.0275))
t = 6.38758965414661
It takes roughly 6.3876 years for the deposit to double. If you need this to the nearest whole number, then round up to 7. We don't round to 6 because then we would come up short of the goal of doubling the deposit.
The answer for A . 2/3
The answer for B. 1 1/4
Explain
4 pound of flout / 6 loaves
4/6
The common for both number is 2
Divide by 2
4/2 = 2
6/2 = 3
And for b
Here the picture
Below
Answer:
The x coordinates and y coordinates will switch places with each other.
Step-by-step explanation:
A' coordinates will go from (x,y) to (y,x) so the coordinates will switch.
Number of Newspaper Published in a day = 300,000
Each news paper must include a Comic section. To check whether each newspaper has comic section or not, the publisher must make a sample Size of 500 or 1,000 will be good . That is , the publisher has to check between Sample size of either 600 or 300 newspapers ,whether it contain a comic section or not.
So, Just Taking a newspaper from a sample size of 600 or 1500 newspapers or 500 or 1000 newspaper and then checking whether it contains Comic section or not will be best way that publisher can adopt.
Time must be kept in mind by the publisher while choosing the sample size.
So basically, the first question after the word problem is asking you to write an equation to represent the value of Mama's car after a certain amount of years (t). Since the value of her car decreases by 3% each year, you could multiply 3% by the original value of her car, to find what 3% is, OR you could subtract 19,400 (the value of her car after 1 year) from 20,000 INSTEAD of multiplying 20,000 by 3%.
Equation: value=20,000 - 600t
To answer the next question, just plug it into the equation you created.
500<20,000 - 600t
-19500< -600t
32.5>t
Final Answer: It would take at least 32 and 1/2 years for the value of Mama's car to be less than $500.
Hope this helps!! :)
