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3 years ago

Help me pleasee;) ..

Mathematics

1 answer:

harkovskaia [24]3 years ago

5 0

The answer for A . 2/3
The answer for B. 1 1/4

Explain

4 pound of flout / 6 loaves

4/6

The common for both number is 2

Divide by 2

4/2 = 2

6/2 = 3

And for b

Here the picture

Below

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3/5 and 4/7 common denominator

dem82 [27]

There is only one common denominator for 3/5 and 4/7. That is 35. To find this, you can multiply the denominators (5 by 7):

5(7)=35

This means that a common denominator of 3/5 and 4/7 is 35.

4 0

3 years ago

Simplify 12^3/12^7 A. 12^4 B 1/12^4 C 1/12^-4 D 12^10

mrs_skeptik [129]

The answer is B.

Explanation:

If you divide exponents, you subtract the exponents.

8 0

3 years ago

Read 2 more answers

X2 2 ab ab to b The diagian K n shows rectangle. The shade Find x.

Norma-Jean [14]

Answer:

x = 28 cm

Step-by-step explanation:

Given:

Area of link shaded regions = 84 cm²

Required:

The value of x (diameter of the semicircle/length of the rectangle)

Solution:

Diameter of the semicircle = 2r = x

Length of rectangle (L) = 2r = x

Radius of semicircle (r) = ½x

Width of rectangle (W) = radius of semicircle = ½x

Use 3.14 as π

Area of the link shaded regions = area of rectangle - area of semicircle

Thus:

Area of the link shaded regions = (L*W) - (½*πr²)

Plug in the values

84 = (x*½x) - (½*3.14*(½x)²)

84 = x²/2 - (1.57*x²/4)

84 = x²(½ - 1.57/4)

84 = x²(0.5 - 0.3925)

84 = x²(0.1075)

Divide both sides by 0.1075

84/0.1075 = x²

781.4 = x²

√781.4 = x

27.9535329 = x

x = 28 cm

5 0

3 years ago

I BET NO ONE KNOWS THIS A rare cooking spice with no close substitutes is an example of a product that is:

DaniilM [7]

Answer:

I think that it is...

Step-by-step explanation:

A. Elastic?

3 0

2 years ago

Will reward brainliest!

Lina20 [59]

Option D: Two irrational solutions

Explanation:

The equation is $17+3 x^{2}=6 x$

Subtracting 6x from both sides, we have,

$3x^{2} -6x+17=0$

Solving the equation using quadratic formula,

$x=\frac{6 \pm \sqrt{36-4(3)(17)}}{2(3)}$

Simplifying the expression, we get,

$\begin{aligned}x &=\frac{6 \pm \sqrt{36-204}}{6} \\&=\frac{6 \pm \sqrt{-168}}{6} \\&=\frac{6 \pm 2 i \sqrt{42}}{6}\end{aligned}$

Taking out the common terms and simplifying, we have,

$\begin{aligned}x &=\frac{2(3 \pm i \sqrt{42})}{6} \\&=\frac{(3 \pm i \sqrt{42})}{3}\end{aligned}$

Dividing by 3, we get,

$x=1+i \sqrt{\frac{14}{3}}, x=1-i \sqrt{\frac{14}{3}}$

Hence, the equation has two irrational solutions.

8 0

3 years ago