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Aleksandr-060686 [28]
3 years ago
15

What is 1 fifth of a clock?

Mathematics
2 answers:
Whitepunk [10]3 years ago
6 0
2.4 hours or 2 hours and 24 minutes represents \frac{1}{5} of a clock. 

The easiest way to find this is to divide 12 by 5 since there are twelve hours on a clock. 
I got the 24 minutes by multiplying 60(minutes there are in an hour) by .4 and got 24.
lbvjy [14]3 years ago
3 0
2.4 hours or 2 hours and 24 minutes Is 1 fifth of a clock
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Solve the equation uding the most direct method: 3x(x+6)=-10?​
Tanzania [10]

To solve this problem, you will use the distributive property to create an equation that can be rearranged and solved using the quadratic formula.

<h3>Distribute</h3>

Use the distributive property to distribute 3x into the term (x + 6):

3x(x+6)=-10

3x^2+18x=-10

<h3>Rearrange</h3>

To create a quadratic equation, add 10 to both sides of the equation:

3x^2+18x+10=-10+10

3x^2+18x+10=0

<h3>Use the Quadratic Formula</h3>

The quadratic formula is defined as:

\displaystyle x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

The model of a quadratic equation is defined as ax² + bx + c = 0. This can be related to our equation.

Therefore:

  • a = 3
  • b = 18
  • c = 10

Set up the quadratic formula:

\displaystyle x=\frac{-18 \pm \sqrt{(18)^2 - 4(3)(10)}}{2(3)}

Simplify by using BPEMDAS, which is an acronym for the order of operations:

Brackets

Parentheses

Exponents

Multiplication

Division

Addition

Subtraction

Use BPEMDAS:

\displaystyle x=\frac{-18 \pm \sqrt{324 - 120}}{6}

Simplify the radicand:

\displaystyle x=\frac{-18 \pm \sqrt{204}}{6}

Create a factor tree for 204:

204 - 1, 2, 3, 4, 6, 12, 17, 34, 51, 68, 102 and 204.

The largest factor group that creates a perfect square is 4 × 51. Therefore, turn 204 into 4 × 51:

\sqrt{4\times51}

Then, using the Product Property of Square Roots, break this into two radicands:

\sqrt{4} \times \sqrt{51}

Since 4 is a perfect square, it can be evaluated:

2 \times \sqrt{51}

To simplify further for easier reading, remove the multiplication symbol:

2\sqrt{51}

Then, substitute for the quadratic formula:

\displaystyle x=\frac{-18 \pm 2\sqrt{51}}{6}

This gives us a combined root, which we should separate to make things easier on ourselves.

<h3>Separate the Roots</h3>

Separate the roots at the plus-minus symbol:

\displaystyle x=\frac{-18 + 2\sqrt{51}}{6}

\displaystyle x=\frac{-18 - 2\sqrt{51}}{6}

Then, simplify the numerator of the roots by factoring 2 out:

\displaystyle x=\frac{2(-9 + \sqrt{51})}{6}

\displaystyle x=\frac{2(-9 - \sqrt{51})}{6}

Then, simplify the fraction by reducing 2/6 to 1/3:

\boxed{\displaystyle x=\frac{-9 + \sqrt{51}}{3}}

\boxed{\displaystyle x=\frac{-9 - \sqrt{51}}{3}}

The final answer to this problem is:

\displaystyle x=\frac{-9 + \sqrt{51}}{3}

\displaystyle x=\frac{-9 - \sqrt{51}}{3}

3 0
2 years ago
Marking brainliest if u do this
Gnesinka [82]

Answer:

Courage is about doing what you believe needs to be done — not in the absence of fear but in spite of it.

Kindness. Kindness is about treating others the way you want to be treated.

Step-by-step explanation:

8 0
3 years ago
Through: (-3, 3) and (0, -1)
Goshia [24]

Answer:

m=3/-4

Step-by-step explanation:

m= x(2)-x(1) / y(2)-y(1)=(0--3)/ (-1-3)=3/-4

7 0
3 years ago
Express 0.3°8° in form a/b where by b#0​
Harlamova29_29 [7]

Answer:

0.3° = 0.3π/180

8° = 2π/45

Multiplying both

0.3π/180×2π/45

3/10π/180 × 2π/45

You will get

π/300 × π/45

= π²/13500 where a = π² b= 13500

Hope this helps.

4 0
3 years ago
Communicate mathematical ideas why might you want to use the commutative property to change the order of the integers in the fol
Kruka [31]

I might want to use the commutative property to change the order of the integers in the following sum before adding the given expression

"-80 + (-173)+(-20)"

As commutative property states that " Changing the order of addends does not change the sum" which means if we add 'a' to 'b' or 'b' to 'a', we will get the same answer.

Therefore, here if we add '-80' to '-173' or '-173' to '-80' , or if we add '-173' to '-20' or '-20' to '-173' , we will get the same answer.

Therefore, we might use commutative property to change the order the of integers in the following sum.

7 0
3 years ago
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