Question

An ice cream cone has a height of 4 in and a radius of 1 in. If the cone is 0.1 in thick, what is the difference (in in3) between the volume of the cone, including the shell, and the volume of the ice cream you can fit inside the shell

Answer 1

Answer:

$0.79 in^3$

Step-by-step explanation:

Given data for the cone

height h= 4 in

radius r= 1 in

hence diameter d= 2 in

thickness of cone= 0.1 in

The volume of the cone including the shell can be expressed as

$volume=\frac{1}{3} \pi r^2h$

$volume= \frac{1}{3}*3.142*1^2*4\\\volume= \frac{12.568}{3} \\\volume= 4.189 in^3$

The volume of the ice cream can be expressed as

N/B: the diameter of the ice cream is

2-(0.1*2)= 2-0.2= 1.8 in

hence the radius is 0.9 in

$volume= \frac{1}{3}*3.142*0.9^2*4\\\ volume= \frac{10.18}{3} \\\ volume= 3.39 in^3$

The difference in volume is $4.189-3.39= 0.79 in^3$