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3 years ago

8

An ice cream cone has a height of 4 in and a radius of 1 in. If the cone is 0.1 in thick, what is the difference (in in3) betwee

n the volume of the cone, including the shell, and the volume of the ice cream you can fit inside the shell

1 answer:

SSSSS [86.1K]3 years ago

8 0

Answer:

$0.79 in^3$

Step-by-step explanation:

Given data for the cone

height h= 4 in

radius r= 1 in

hence diameter d= 2 in

thickness of cone= 0.1 in

The volume of the cone including the shell can be expressed as

$volume=\frac{1}{3} \pi r^2h$

$volume= \frac{1}{3}*3.142*1^2*4\\\volume= \frac{12.568}{3} \\\volume= 4.189 in^3$

The volume of the ice cream can be expressed as

N/B: the diameter of the ice cream is

2-(0.1*2)= 2-0.2= 1.8 in

hence the radius is 0.9 in

$volume= \frac{1}{3}*3.142*0.9^2*4\\\ volume= \frac{10.18}{3} \\\ volume= 3.39 in^3$

The difference in volume is $4.189-3.39= 0.79 in^3$

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