Answer:
No, and solutions is is not valid.
Step-by-step explanation:
Solving y'(x)= y(x)a|x| by parts yields y(x)=
is the solutions, for y(0)=0 (initial value), it yields 
which is not valid. Note a is assumed to be constant.
35 43
- 15 -26. 20 to 17
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20 17
Answer:
y-1=-6(x+3)
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(-5-1)/(-2-(-3))
m=-6/(-2+3)
m=-6/1
m=-6
y-y1=m(x-x1)
y-1=-6(x-(-3))
y-1=-6(x+3)
Based on the given roots and their multiplicities, the function is made of the following factors:
f(x) = x (x + 3)^2 (x - 1) (x - 3)^2
The roots represent the point in the graph where they touch the x-axis. With the given condition that the function has a positive leading coefficient and is of even degree, the group of the function touches the x-axis at the roots and is curved upwards.
