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Art [367]
3 years ago
6

Factorise y squared -9w squared

Mathematics
1 answer:
Jlenok [28]3 years ago
6 0
Y^2 - 9w^2
= y^2 - 3^2w^2
=(y + 3w)(y - 3w)
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Can you someone answer this with solution
zaharov [31]

Answer: A. . . . . . . . . .

I can’t do that check mark thing so I’ll use ! instead.

!12+2!8-12!2

!12 2!8

2!3+2!8-12!2

!8 2!2

2!3+2x2!2-12!2

2x2!2 4!2

2!3+4!2-12!2

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6 0
3 years ago
Can someone explain this step by step? I'm very confused on how to solve it. Thanks!
Rashid [163]

Answer:

x = -8

Step-by-step explanation:

I will show each step algebraically. If you need further explanation, feel free to ask questions :)

\frac{x}{2} +7=3\\                     Rewrite

\frac{x}{2} =-4                        Subtract 7

x =-8                        Multiply by reciprocal (2/1)

I hope this helps!

3 0
3 years ago
Read 2 more answers
Solve for X<br><br> PLEASE HELP ME
guapka [62]

Answer:

x = 10°

Step-by-step explanation:

Step 1:

92° + x° + 78° = 180°             Supplementary Angles

Step 2:

x° + 170° = 180°         Combine Like Terms

Step 3:

x° = 180° - 170°       Subtract 170° on both sides

Answer:

x = 10°

Hope This Helps :)

4 0
3 years ago
Jessie's bus ride to school is 5 minutes more then 2/3 the time roberts bus ride. if jessie's time riding the bus is y and rober
Rainbow [258]
X=2/3y because you want to know what roberts time is
7 0
4 years ago
Two points are selected randomly on a line of length 32 so as to be on opposite sides of the midpoint of the line. In other word
Paladinen [302]

Solution :

Let us consider the squares be $[1, 16] \times [16, 32]$

If x ranges from the 0 to 16 and the y ranges from 16 to 32, we see that the boundary of the region$y-x \geq 9 \text{\ is}\ y - x = 9$  which goes from the $(7, 16  ) \text{ to}\ (16, 25) $.

And so it is easier to find the area of region where $ y-x \leq 9$. This is the triangle with points $(7,16),(16,25) \text{ and}\ (16,16)$ as its vertices.

The area if the triangle is =  $\frac{1}{2} \times 9 \times 9$

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Now the entire area is $(16)^2$  = 256

Then, $P(y-x \leq 9) = \frac{81/2}{256} =\frac{81}{512}$

or $P(y-x \geq 9) = 1 - \frac{81}{512}=\frac{431}{512}$

Thus the answer is $\frac{431}{512}$

4 0
3 years ago
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