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uysha [10]
3 years ago
8

Amita's kitchen is rectangular with an area of 3 3 4 square meters. The width of the kitchen is 1 1 2 meters. What is the length

, in meters, of Amita's kitchen?
Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
3 0

Answer:

2 1/2 meters

Step-by-step explanation:

Amita's kitchen is rectangular with an area of 3 3 /4 square meters. The width of the kitchen is 1 1/ 2 meters. What is the length, in meters, of Amita's kitchen?

The formula for the area of a rectangle = Length × Width.

To find the length our formula becomes : Area/Width

In the question,

Area = 3 3/4 m²

Width = 1 1/2 m

Length of the rectangular kitchen

= 3 3/4 m² ÷ 1 1/2 m

= 15/4 m² ÷ 3/2 m

= 15/4 m² × 2/3 m

= 5/2 m

= 2 1/2 m

The length of the rectangular kitchen is 2 1/2 meters

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Answer:

a.2:7

b.7:9

c.4:5

hope it helps

Explanation -

a. as original ratio is 10/35 , we reduce it to 2:7.

b. as original ratio is 35/45 , we reduce it to 7:9

c. as original ratio is 40:50 , we reduce it to 4:5

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Find the value of x.<br> 105°<br> (10x – 5)
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Answer:

 525o • (2x - 1)

Step-by-step explanation:

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IgorLugansk [536]

Answer:

1 = 115°

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3 0
3 years ago
Read 2 more answers
Christopher works at the power plant for the southwest part of his home state. For peak operational performance, his department
Licemer1 [7]

Answer:

B) To maintain peak performance for every 50 generators, there are 10 inspectors.

Step-by-step explanation:

For peak operational:

3 electricians for each generator.  ⇒  1 Generator : 3 Electricians

4 inspectors for every 60 electricians. ⇒  60 Electricians : 4 Inspectors

Now, the number of generators the state has now = 50

Let us assume the number of  inspectors  required by the power plant  = m

Now, from the given ratios:

For, 3 electrician there  is 1 generator

⇒ For, 3 x 20 Electrician  there is 1  x 20 Generators.

or, for 60 Electrician there are 20 Generators.   (1)

Also, for 60 Electrician there are 4 inspectors.    (2)

⇒From (1) and (2), we get:

For every 20 generators, there are 4 inspectors.

And, from what we have assumed  For every 50 generators, there are m inspectors.

So, by the RATIO OF PROPORTION:

\frac{20}{4}  = \frac{50}{m}\\ \implies  m = 50 \times\frac{4}{20}  = 10

or, m = 10

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3 0
4 years ago
In a study of the impact of smoking on birth weight, researchers analyze birth weights (in grams) for babies born to 189 women w
kompoz [17]

Answer:

c. Smoking is associated with lower birth weights. When smokers are compared to nonsmokers, we are 95% confident that the mean weight of babies born to nonsmokers will be between 76.5 grams to 486.9 grams more than the mean birth weight of babies born to smokers.

Step-by-step explanation:

The difference in mean birth weights (nonsmokers minus smokers) is 281.7 grams with a margin of error of 205.2 grams with 95% confidence.

Then, we know that the 95% confidence interval is (76.5, 486.9)

LL=M-MOE=281.7-205.2=76.5\\\\UL=M-MOE=281.7+205.2=486.9

<em>a. We are 95% confident that smoking causes lower birth weights by an average of between 76.5 grams to 486.9 grams.</em>

False, it interprets the confidence interval as a probability for individual cases. The confidence interval is a range for the population mean.

<em>b. There is a 95% chance that if a woman smokes during pregnancy her baby will weigh between 76.5 grams to 486.9 grams less than if she did not smoke.</em>

False, it interprets the confidence interval as a probability for individual cases. The confidence interval is a range for the population mean.

<em>c. Smoking is associated with lower birth weights. When smokers are compared to nonsmokers, we are 95% confident that the mean weight of babies born to nonsmokers will be between 76.5 grams to 486.9 grams more than the mean birth weight of babies born to smokers.</em>

True.

<em>d. With such a large margin of error, this study does not suggest that there is a difference in mean birth weights when we compare smokers to nonsmokers.</em>

There is enough evidence, as the lower bound of the confidence is positive. This means that there is only a probability of 0.05/2=0.025 that the true mean weight difference is smaller than 76.5 grams.

6 0
3 years ago
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