Answer:
The srarement is false foor any value
Step-by-step explanation:
Let <em>f(x)</em> = <em>x</em>³ + <em>x</em> - 5. <em>f(x)</em> is a polynomial so it's continuous everywhere on its domain (all real numbers). Since
<em>f</em> (1) = 1³ + 1 - 5 = -3 < 0
and
<em>f</em> (2) = 2³ + 2 - 5 = 5 > 0
it follows by the intermediate value theorem that there at least one number <em>x</em> = <em>c</em> between 1 and 2 for which <em>f(c)</em> = 0.
The answer is 79 and 80.
x - the number of the first locker
x + 1 - the number of the consecutive locker
Their sum is 159.
x + x + 1 = 159
2x + 1 = 159
2x = 159 - 1
2x = 158
x = 158 / 2
x = 79
x - the number of the first locker: x = 79
x + 1 - the number of the consecutive locker x + 1 = 79 + 1 = 80
Answer:
10,014,070
Step-by-step explanation:
Answer:
In D
Step-by-step explanation:
in d you can place the lamp there
