What is the equation of the line that passes through the point (8, 8) and has a slope of -22
1 answer:
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To solve first move the 98 to the other side by subtracting it from both sides. Then divide by - 1 on both sides to that the x^2 is no longer a negative. You are left with:
Now square root both sides to get
The two factors that make up 98 are 49 and 2. 49 can be square rooted. So we are left with these answers:
and 
Now square root both sides to get
The two factors that make up 98 are 49 and 2. 49 can be square rooted. So we are left with these answers:
Answer:
(x, y) = (2, -3/4)
Step-by-step explanation:
The point of the "elimination" technique is to combine the equations in a way that eliminates one of the variables. Sometimes this involves multiplying one or both of the equations by constants before you add those results together. In any event, the first step is to look at the coefficients of the variable terms to see if there is a simple combination of them that will result in zero.
The y terms have coefficients that are opposites of each other (4, -4), so you can simply add the two equations to eliminate y as a variable.
(2x +4y) +(x -4y) = (1) +(5)
3x = 6 . . . . . simplify
x = 2 . . . . . . divide by 3
Now, you find y by substituting this value into one of the equations. I would choose the equation with the positive y-coefficient:
2(2) +4y = 1
4y = -3 . . . . . . subtract 4
y = -3/4
Then the solution is ...
(x, y) = (2, -3/4)
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A graphing calculator confirms this solution.
