Points A, B, C, and D lie on line segment AD. If AB = x, BC = x + 3, CD = twice the length of BC, and AD = 53, what is the value of x? What is the length of BC?
2 answers:
Point A the beginning of line and point D end of the line segment So ,x+x+3 +2(x+3)=53 2x+3+2x+6=53 4x+9 =53 4x =44 x=11 length of BC is 2(11+3)=28
Answer:
x=11, BC = 14
Step-by-step explanation:
Points A, B, C, and D lie on line segment AD. If AB = x, BC = x + 3, CD = twice the length of BC, and AD = 53, what is the value of x? What is the length of BC?
AB=X AB=11
BC=X + 3 BC= 11 + 3= 14
CD= 2(X + 3) CD= 2(11 + 3)= 28
11+14+28=53
AD= 53
X + X + 3 + 2(X + 3) =53
2x+3+2x+6=53
4x+9 =53
<u>-9= -9</u>
<u>4x =44</u>
4 4
x=11
length of BC is 11 + 3 = 14
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