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algol [13]
3 years ago
10

The perimeter of a rectangle is 140 feet. The length of the rectangle is 6 more than 2 times the width. What is the length of th

e rectangle?
Mathematics
1 answer:
Alja [10]3 years ago
5 0
The equations we get are
l = 6 + 2w (We get this from "The length of the rectangle is 6 more than 2 times the width.")
and
2l + 2w = 140 (We get this from the perimeter. Two times the length plus two times the width equals the perimeter of a quadrilateral.)

The first equation can be written as
l - 2w = 6

So now we have
2l + 2w = 140
l - 2w = 6
____________
Add the two equations.
We get 3l = 146

Divide by 3 on both sides.
l = 48\frac{2}{3}

Your answer is 48\frac{2}{3}.
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From the identities above, you have

\sin^22x\cos^22x=\dfrac{(1-\cos4x)(1+\cos4x)}4=\dfrac{1-\cos^24x}4

Applying once more, you have

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Answer:

The answer is (C)

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3 years ago
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8 0
2 years ago
9x-2y=11 <br> 5x-2y=15 <br> what is the solution to the above system of equations<br> ASAP
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Subtracting equation (ii) from (i) we get;

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3 years ago
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The appropriate choice is (B) 10.

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3 years ago
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