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algol [13]
3 years ago
10

The perimeter of a rectangle is 140 feet. The length of the rectangle is 6 more than 2 times the width. What is the length of th

e rectangle?
Mathematics
1 answer:
Alja [10]3 years ago
5 0
The equations we get are
l = 6 + 2w (We get this from "The length of the rectangle is 6 more than 2 times the width.")
and
2l + 2w = 140 (We get this from the perimeter. Two times the length plus two times the width equals the perimeter of a quadrilateral.)

The first equation can be written as
l - 2w = 6

So now we have
2l + 2w = 140
l - 2w = 6
____________
Add the two equations.
We get 3l = 146

Divide by 3 on both sides.
l = 48\frac{2}{3}

Your answer is 48\frac{2}{3}.
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2 years ago
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Answer:

Below in BOLD.

Step-by-step explanation:

5x^2 - 6x - 2 = 0

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x =  [-b ± √(b^2 - 4ac)]/ 2a    

Here we have a = 5, b = -6 and c = -2

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=  [ 6 ± √(36 + 40)] / 10

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= 1.4718,  -0.2718

= 1.5, -0.3 to one decimal place.

x^2 + 3x = 40

x^2 + 3x - 40 = 0

We can factor this one:

(x - 5)(x + 8) = 0

x - 5 = 0 giving x = 5 and

x + 8 = 0 giving x = -8.

Answer  x = -8, 5.

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Read 2 more answers
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