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solong [7]
3 years ago
15

Affirmative action commitments by many organizations have led to an increase in the number of women in executive positions. Sate

llite Office Systems has vacancies for two executives that it will fill from among four women and six men. What is the probability that at least one woman is selected
Mathematics
1 answer:
Ira Lisetskai [31]3 years ago
5 0

Answer:

2/3

Step-by-step explanation:

We solve with combination formula

C(n, r) = nCr = n!/r!( n - r)!

The selection will happen between four women and six men

Total number of people = Total number of possibly outcomes = Four women + six men

= 10 people

This can happen in two ways

a) 2 women

b) 1 man and 1 woman

The probability that at least one woman is selected =

4C2 ×(6C1 + 4C1)÷ 2 ways / 10C2

[6 × (6+ 4)] ÷ 2 / 45

= (6 × 10) ÷ 2/45

= 30/45

= 2/3

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\bf \begin{array}{ccll}&#10;\stackrel{inches}{drawing}&\stackrel{feet}{actual}\\&#10;\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\&#10;\frac{1}{4}&12\\\\&#10;d&15&#10;\end{array}\implies \cfrac{\quad \frac{1}{4}\quad }{d}=\cfrac{12}{15}\implies \cfrac{\quad \frac{1}{4}\quad }{\frac{d}{1}}=\cfrac{12}{15}&#10;\\\\\\&#10;\cfrac{1}{4}\cdot \cfrac{1}{d}=\cfrac{12}{15}\implies \cfrac{1}{4d}=\cfrac{12}{15}\implies 15=48d\implies \cfrac{15}{48}=d\implies \cfrac{5}{16}=d
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