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solong [7]
2 years ago
15

Affirmative action commitments by many organizations have led to an increase in the number of women in executive positions. Sate

llite Office Systems has vacancies for two executives that it will fill from among four women and six men. What is the probability that at least one woman is selected
Mathematics
1 answer:
Ira Lisetskai [31]2 years ago
5 0

Answer:

2/3

Step-by-step explanation:

We solve with combination formula

C(n, r) = nCr = n!/r!( n - r)!

The selection will happen between four women and six men

Total number of people = Total number of possibly outcomes = Four women + six men

= 10 people

This can happen in two ways

a) 2 women

b) 1 man and 1 woman

The probability that at least one woman is selected =

4C2 ×(6C1 + 4C1)÷ 2 ways / 10C2

[6 × (6+ 4)] ÷ 2 / 45

= (6 × 10) ÷ 2/45

= 30/45

= 2/3

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Liono4ka [1.6K]

Answer:

288

Step-by-step explanation:

24 = 8 1/3 % of x

24 = (25/3 * 1/100)x

25/300 x = 24

x = 24 * 300/25

x = 7200/25

x = 288

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2 years ago
Consider the equation 4x + 1 = 2x + 5
Darya [45]

(a) Without solving the equation we can't determine whether its true or false.

(b) If x = 3

4x + 1 = 2x + 5

4(3) + 1 = 2(3) + 5

12 + 1 = 15 + 5

13 = 20

No, if x = 3, the equation will not be true.

(c) 4x + 1 = 2x + 5

4x - 2x = 5 - 1

2x = 4

x = 4/2

x = 2

This shows that x = 2 makes the equation true.

8 0
3 years ago
Here are the endpoints of the segments BC, FG, and JK.<br> B, −67
yulyashka [42]

~~~~~~~~~~~~\textit{distance between 2 points} \\\\ B(\stackrel{x_1}{-6}~,~\stackrel{y_1}{7})\qquad C(\stackrel{x_2}{-4}~,~\stackrel{y_2}{4})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ BC=\sqrt{[-4 - (-6)]^2 + [4 - 7]^2}\implies BC=\sqrt{(-4+6)^2+(-3)^2} \\\\\\ BC=\sqrt{2^2+(-3)^2}\implies \boxed{BC=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ ~~~~~~~~~~~~\textit{distance between 2 points}

F(\stackrel{x_1}{-2}~,~\stackrel{y_1}{-4})\qquad G(\stackrel{x_2}{1}~,~\stackrel{y_2}{-2})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ FG=\sqrt{[1 - (-2)]^2 + [-2 - (-4)]^2}\implies FG=\sqrt{(1+2)^2+(-2+4)^2} \\\\\\ FG=\sqrt{9+4}\implies \boxed{FG=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ J(\stackrel{x_1}{4}~,~\stackrel{y_1}{2})\qquad K(\stackrel{x_2}{5}~,~\stackrel{y_2}{-2})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}

JK=\sqrt{[5 - 4]^2 + [-2 - 2]^2}\implies JK=\sqrt{1^2+(-4)^2}\implies \boxed{JK=\sqrt{17}} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \overline{BC}\cong \overline{FG}~\hfill

4 0
1 year ago
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