Answer:
2/3
Step-by-step explanation:
We solve with combination formula
C(n, r) = nCr = n!/r!( n - r)!
The selection will happen between four women and six men
Total number of people = Total number of possibly outcomes = Four women + six men
= 10 people
This can happen in two ways
a) 2 women
b) 1 man and 1 woman
The probability that at least one woman is selected =
4C2 ×(6C1 + 4C1)÷ 2 ways / 10C2
[6 × (6+ 4)] ÷ 2 / 45
= (6 × 10) ÷ 2/45
= 30/45
= 2/3
