The answer is D. I’m assuming this is surface area so here’s my explanation:) ok so the area of the triangle is 6 (4x3 divided by 2) and when you add the other triangle that’s 12. Ok so we have 12 so far. Then the area of the bottom rectangle is 24 (3x8). Then the area of the side rectangle is 32 (4x8). THEN the top rectangle’s area is 40 (8x5). When you add the numbers up (12+24+32+40) you get 108! And of course dont forget the cm2. ( centimeters squared ). :) I hope this helps
Answer:
Step-by-step explanation:
Yes
Answer:
The area of triangle K is 16 times greater than the area of triangle J
Step-by-step explanation:
we know that
If Triangle K is a scaled version of Triangle J
then
Triangle K and Triangle J are similar
If two triangles are similar, then the ratio of its areas is equal to the scale factor squared
Let
z -----> the scale factor
Ak ------> the area of triangle K
Aj -----> the area of triangle J
so

we have

substitute



therefore
The area of triangle K is 16 times greater than the area of triangle J
The red one is A-49 P-28. Orange is A-96 P-40
Answer:
33
Step-by-step explanation:
1254 divided by 38 is 33