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Maslowich
3 years ago
13

21) Solve x2 - 13x - 30 = 0 by factoring.

Mathematics
2 answers:
stepan [7]3 years ago
7 0

Answer:

x=15 or x=-2

Step-by-step explanation:

x^2-13x-30=0

First find the multiples of 30 that will also equal to 13.

6*5=30 ,15*2=30 and 10*3=30

  1. x^2-15x+2x-30=0
  2. x(x-15)+2(x-15)=0
  3. (x-15)(x-2)=0
  4. x-15=0 or x+2=0
  5. x=15 or x=-2
stellarik [79]3 years ago
3 0

Answer:

x= 15, -2!!!!!!!!!!!!!!

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10x-61/12 is the difference of  (7x-6\frac{2}{3}) - (-3x + 4\frac{3}{4}).

<h3>What is Expression?</h3>

An expression is combination of variables, numbers and operators.

The given expression is (7x-6\frac{2}{3}) - (-3x + 4\frac{3}{4})

7x-6\frac{2}{3}+3x- 4\frac{3}{4}

7x-20/3+3x-19/4

Add the variable terms and constant terms.

10x-20/3-19/4

The LCM of 3 and 4 is 12/

10x-4-57/12

10x-61/12

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Find the nth term of the sequence:<br>23, 19, 13, 5, -5.......<br>​
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Step-by-step explanation:

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19 - 23 = -4

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A man bought a horse and carriage for $500 paying three times as much for the carriage as for the horse how much did each cost
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A rocket is launched from a tower. The height of the rocket, y in feet, is related to the
devlian [24]

Answer:

The rocket will reach its maximum height after 6.13 seconds

Step-by-step explanation:

To find the time of the maximum height of the rocket differentiate the equation of the height with respect to the time and then equate the differentiation by 0 to find the time of the maximum height

∵ y is the height of the rocket after launch, x seconds

∵ y = -16x² + 196x + 126

- Differentiate y with respect to x

∴ y' = -16(2)x + 196

∴ y' = -32x + 196

- Equate y' by 0

∴ 0 = -32x + 196

- Add 32x to both sides

∴ 32x = 196

- Divide both sides by 32

∴ x = 6.125 seconds

- Round it to the nearest hundredth

∴ x = 6.13 seconds

∴ The rocket will reach its maximum height after 6.13 seconds

There is another solution you can find the vertex point (h , k) of the graph of the quadratic equation y = ax² + bx + c, where h = -\frac{b}{2a} and k is the value of y at x = h and k is the maximum/minimum value

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∴ x = 6.13 seconds

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