10x-61/12 is the difference of (7x-
) - (-3x +
).
<h3>What is Expression?</h3>
An expression is combination of variables, numbers and operators.
The given expression is (7x-
) - (-3x +
)
7x-
+3x- 
7x-20/3+3x-19/4
Add the variable terms and constant terms.
10x-20/3-19/4
The LCM of 3 and 4 is 12/
10x-4-57/12
10x-61/12
Hence, 10x-61/12 is the difference of (7x-
) - (-3x +
).
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Answer:
Step-by-step explanation:
Given the sequence :
23, 19, 13, 5, -5.......
From the sequence, the common difference is unequal, as their is a constant Increment in the difference after successive numbers.
19 - 23 = -4
13 - 19 = -6
5 - 13 = -8
-5 - 5= -10
Hence an constant difference of - 2 after each successive difference.
Hence, this is a quadratic sequence
With the formula
an² + bn + c
Hello! So, in order to solve this question, we should do 500/4. 500/4 = 125. Multiply 125 by 3 and you get 375. The horse costs $125 and the carriage costs $375.
Answer:
The rocket will reach its maximum height after 6.13 seconds
Step-by-step explanation:
To find the time of the maximum height of the rocket differentiate the equation of the height with respect to the time and then equate the differentiation by 0 to find the time of the maximum height
∵ y is the height of the rocket after launch, x seconds
∵ y = -16x² + 196x + 126
- Differentiate y with respect to x
∴ y' = -16(2)x + 196
∴ y' = -32x + 196
- Equate y' by 0
∴ 0 = -32x + 196
- Add 32x to both sides
∴ 32x = 196
- Divide both sides by 32
∴ x = 6.125 seconds
- Round it to the nearest hundredth
∴ x = 6.13 seconds
∴ The rocket will reach its maximum height after 6.13 seconds
There is another solution you can find the vertex point (h , k) of the graph of the quadratic equation y = ax² + bx + c, where h =
and k is the value of y at x = h and k is the maximum/minimum value
∵ a = -16 , b = 196
∴ 
∴ h = 6.125
∵ h is the value of x at the maximum height
∴ x = 6.125 seconds
- Round it to the nearest hundredth
∴ x = 6.13 seconds