If a rectangler has an area of 34 and the width is half the length what are the length and the width

1 answer:

3 0

A=LW,

W=L/2, L=2W so:

A=(2W)W

A=2W^2 and A=34 so:

2W^2=34

W^2=17

W=√17, and since L=2W

L=2√17

So the length is 2√17 and the width is √17

(length≈8.25 and width≈4.12 if you wanted approximations...)

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D; x -y = 22

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Step-by-step explanation:

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