If a rectangler has an area of 34 and the width is half the length what are the length and the width
1 answer:
A=LW,
W=L/2, L=2W so:
A=(2W)W
A=2W^2 and A=34 so:
2W^2=34
W^2=17
W=√17, and since L=2W
L=2√17
So the length is 2√17 and the width is √17
(length≈8.25 and width≈4.12 if you wanted approximations...)
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