A triangular frame has sides that measure 15'-7",20'-4" and 26'-2". What is the total length of three sides?
1 answer:
we know that
<u>Part 1) </u>
we know that
side 1=15'-7"
side 2=20'-4"
side 3=26'-2"
To find the total length of three sides sum the three sides
so
total length=side 1+side 2 +side 3
substitute
total length=15'-7"+20'-4"+26'-2"
total length=(15'+20'+26')+(7"+4"+2")
total length=(61')+(13")
remember that
12"=1'
13"=12"+1"=1'+1"
substitute
total length=(61')+(1'+1")
total length=(62')+(1")---------> 62'-1"
therefore
<u>the answer is</u>
the total length of three sides is 62'-1"
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Given:
The domain of function that is translated down 3 is (0, 4), (-5, 8), (4, -2).
To find:
The range of the function.
Solution:
If a function is translated 3 units down, then
Using this rule, we get
Similarly,
The range of the given function is (0, 1), (-5, 5), (4, -5).
Therefore, the correct option is A.