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3 years ago

Use the rule y=4 -2x to work out if x =0 what does y =

Mathematics

2 answers:

zheka24 [161]3 years ago

7 0

If we look at our values for X and Y in the example problem, we see that we have -2 and 8. If X is -2, then 8 is 10 digits larger than -2. So, if X is 0, Y is 10.

Murljashka [212]3 years ago

3 0

If x is 0 y will be 4, if x is 1 y will be 2, if x is 2 y will be 0.
Y=4-2x
X=0
soln: 4-2(0) 4-2(1) 4-2(2)
4-0 4-2 4-4
=4 =2 =0

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Which expression is equivalent to -Assume

Elden [556K]

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3 years ago

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a bee flies at 9 feet per second directly to a flower bed from its hive. the bee stays at the flower bed for 15 minutes then fli

qaws [65]

Answer:

Assuming the question is asking how much time it takes each way, the answer would be 2 minutes from the hive to the flowerbed and 3 minutes back.

Assuming the question is the amount of distance between the hive and the flower bed, the answer is 1080 feet.

Step-by-step explanation:

So the total amount of time it was away from the hive was 20 minutes. Out of those 20 minutes, 15 minutes were spent in the flowerbed. So that means travel time was 5 minutes. Now, going is 9 and coming back is 6, so 9+6=15, 5/15=1/3, 1/3*9=3 and 1/3*6=2

Knowing that information, lets solve what the question could be because I have no idea. The amount of distance from the hive to the flower bed is 1080 feet. I got this by doing 9 (the amount of feet per second) times 120 (the amount of seconds in 3 minutes.) You could do this with 6 but I found it easier to multiply 9*120 compared to 6*180.

If it's the commute time, we already solved that.

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4 years ago

Arrange the cones in order from lease volume to greatest volume

bearhunter [10]

Answer:

Volume of the cone in ascending order.

$V_{2}=270\pi\ units^{3}$

cone with DIAMETER of 18 & height of 10

cone with RADIUS of 10 & height of 9

cone with RADIUS of 11 & height of 9

cone with DIAMETER of 20 & height of 12

Step-by-step explanation:

Let $V_{2}. V_{3}. and\ V_{4}.$ be the volume of the cone.

Let d, r and h be the diameter, radius and height of the cone.

Given:

$d_{1} = 20\ and\ h_{1}=12$

$d_{2} = 18\ and\ h_{2}=10$

$r_{3} = 10\ and\ h_{3}=9$

$r_{4} = 11\ and\ h_{14}=9$

Arrange the cones in order from lease volume to greatest volume.

Solution:

The volume of the cone is given below.

$V=\pi r^{2} \frac{h}{3}$ ----------------(1)

where: r is radius of the base of cone.

and h is height of the cone.

The volume of the cone for $d_{1} = 20\ and\ h_{1}=12$

$r_{1} = \frac{d_{1}}{2}$

$r_{1} = \frac{20}{2}=10\ units$

$V_{1}=\pi (r_{1})^{2} \frac{h_{1}}{3}$

$V_{1}=\pi (10)^{2} \frac{12}{3}$

$V_{1}=\pi\times 100\times 4$

$V_{1}=400\pi\ units^{3}$

Similarly, for volume of the cone for $d_{2} = 18\ and\ h_{2}=10$

$r_{2} = \frac{d_{2}}{2}$

$r_{2} = \frac{18}{2}=9\ units$

$V_{2}=\pi (r_{2})^{2} \frac{h_{2}}{3}$

$V_{2}=\pi (9)^{2} \frac{10}{3}$

$V_{2}=\pi\times 81\times \frac{10}{3}$

$V_{2}=\pi\times 27\times 10$

$V_{2}=270\pi\ units^{3}$

Similarly, for volume of the cone for $r_{3} = 10\ and\ h_{3}=9$

$V_{3}=\pi (r_{3})^{2} \frac{h_{3}}{3}$

$V_{3}=\pi (10)^{2} \frac{9}{3}$

$V_{3}=\pi\times 100\times 3$

$V_{3}=\pi\times 300$

$V_{3}=300\pi\ units^{3}$

Similarly, for volume of the cone for $r_{4} = 11\ and\ h_{4}=9$

$V_{4}=\pi (r_{4})^{2} \frac{h_{4}}{3}$

$V_{4}=\pi (11)^{2} \frac{9}{3}$

$V_{4}=\pi\times 121\times 3$

$V_{4}=\pi\times 363$

$V_{4}=363\pi\ units^{3}$

So, the volume of the cone in ascending order.

$V_{2}=270\pi\ units^{3}$

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77julia77 [94]

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3 years ago