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qwelly [4]
3 years ago
9

Evaluate expression

Mathematics
1 answer:
fiasKO [112]3 years ago
4 0
My calculator gave me the answer -43/24. Hope this helps. If its wrong I'm sorry.
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Which type of correlation would you expect to see between the distance traveled and the time it takes to travel that distance? A
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3x + c = 3x + 2<br> i want to know the answers to this equations
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2

Step-by-step explanation:

c=2

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A restaurant's small salt shakers contain 0.6 ounces of salt. It's large shakers hold twice as much. The shakers are filled from
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First you have to multiply the 0.6 of the small shakers times two which gives us 1.2 the amount of salt of the large shakers. divide the 18.6 by 1.2 which is 15.5 the amount going into the 8 shakers. Then subtract 15.5 from 18.6 which gives us 3.1. Then you divide that by 0.6 = 5. 5 small shakers can be filled with the remaining salt.
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Find the surface area of the tool box. Round your answer to the nearest tenth and explain your answer. ​Pls I NEED THE ANSWER NO
Andrej [43]

Answer:

807.8 in^2

Step-by-step explanation:

The total area of the box is the sum of the areas of all faces of the box. The top, bottom, front, and back faces are rectangles 18 in long. The end faces each consist of a rectangle and a triangle. We can compute the sum of these like this:

The areas of top, bottom, front, and back add up to be 18 inches wide by the length that is the perimeter of the end: 2·5in +2·8 in + 9.6 in = 35.8 in. That lateral area is ...

(18 in)(35.6 in) = 640.8 in^2

The area of the triangle on each end is equivalent to the area of a rectangle half as high, so we can compute the area of each end as ...

(9.6 in)(8.7 in) = 83.52 in^2

Then the total area is the lateral area plus the area of the two ends:

640.8 in^2 + 2·83.52 in^2 = 807.84 in^2 ≈ 807.8 in^2

7 0
2 years ago
Suppose an airline policy states that all baggage must be box shaped with a sum of​ length, width, and height not exceeding 114
NISA [10]

Answer:

Step-by-step explanation:

Represent the length of one side of the base be s and the height by h.  Then the volume of the box is V = s^2*h; this is to be maximized.

The constraints are as follows:  2s + h = 114 in.  Solving for h, we get 114 - 2s = h.

Substituting 114 - 2s for h in the volume formula, we obtain:

V = s^2*(114 - 2s), or V = 114s^2 - 2s^3, or V = 2*(s^2)(57 - s)

This is to be maximized.  To accomplish this, find the first derivative of this formula for V, set the result equal to 0 and solve for s:

dV

----- = 2[(s^2)(-1) + (57 - s)(2s)] = 0 = 2s^2(-1) + 114s - 2s^2

ds

Simplifying this, we get dV/ds = -4s^2 + 114s = 0.  Then either s = 28.5 or s = 0.

Then the area of the base is 28.5^2 in^2 and the height is 114 - 2(28.5) = 57 in

and the volume is V = s^2(h) = 46,298.25 in^3

7 0
3 years ago
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