The program is correct: at the beginning, product = 0. Then, we start summing Y to that variable, and we sum Y exactly X times, because with each iteration we increase Count by 1, and check if Count=X so that we can exit the loop.
Answer:
A. the museum can choose a heuristic approach which will achieve a lossless compression, but they cannot be sure that it is the most efficient compression for each image
C. algorithms for lossless compression exist, so the museum can use those to compress the image
Explanation:
