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4 years ago

HELP AS SOON IS A UNIT TEST WILL GIVE BRAINLIEST

Computers and Technology

2 answers:

Crank4 years ago

6 0

Answer:

/ hunh niujhiu ji j90 uj9iuhjuij io6j v96i5 jy 5uy8 5 uytujy5u89 tiyjq4hgtir gj

Explanation:

j truehjt98 4utjr8tguj589r gu5rg8 jgtu jttg89uj8t9y 8gtjuijgf ig vjigjbiow4tjh ithit jhgitgjgtighj54iot ji5 jy8tuh4

sergij07 [2.7K]4 years ago

6 0

Answer:

MERGE AND CENTER just tokk the unit test hope this helps sub to me on you tube at the RESURGENTZ if it did

Explanation:

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What is the CPU Unit of a computer?

denis-greek [22]

Answer:

The computer's central processing unit (CPU) is the portion of a computer that retrieves and executes instructions. The CPU is essentially the brain of a CAD system. It consists of an arithmetic and logic unit (ALU), a control unit, and various registers.

Explanation:

4 0

3 years ago

Read 2 more answers

A(n) ____ is a set of computer instructions.

sesenic [268]

A[n] program is a set of computer instructions.

4 0

3 years ago

Oxnard Casualty wants to ensure that their e-mail server has 99.98 percent reliability. They will use several independent server

sattari [20]

Answer:

The smallest number of servers required is 3 servers

Explanation:

Given

$Reliability = 99.98\%$

$Individual Servers = 95\%$

Required

Minimum number of servers needed

Let p represent the probability that a server is reliable and the probability that it wont be reliable be represented with q

Such that

$p = 95\%\\$

It should be noted that probabilities always add up to 1;

So,

$p + q = 1$ '

Subtract p from both sides

$p - p + q = 1 - p$

$q = 1 - p$

Substitute $p = 95\%\\$

$q = 1 - 95\%$

Convert % to fraction

$q = 1 - \frac{95}{100}$

Convert fraction to decimal

$q = 1 - 0.95$

$q = 0.05$

------------------------------------------------------------------------------------------------

To get an expression for one server

The probabilities of 1 servers having 99.98% reliability is as follows;

$p = 99.98\%$

Recall that probabilities always add up to 1;

So,

$p + q = 1$

Subtract q from both sides

$p + q - q = 1 - q$

$p = 1 - q$

So,

$p = 1 - q = 99.98\%$

$1 - q = 99.98\%$

Let the number of servers be represented with n

The above expression becomes

$1 - q^n = 99.98\%$

Convert percent to fraction

$1 - q^n = \frac{9998}{10000}$

Convert fraction to decimal

$1 - q^n = 0.9998$

Add $q^n$ to both sides

$1 - q^n + q^n= 0.9998 + q^n$

$1 = 0.9998 + q^n$

Subtract 0.9998 from both sides

$1 - 0.9998 = 0.9998 - 0.9998 + q^n$

$1 - 0.9998 = q^n$

$0.0002 = q^n$

Recall that $q = 0.05$

So, the expression becomes

$0.0002 = 0.05^n$

Take Log of both sides

$Log(0.0002) = Log(0.05^n)$

From laws of logarithm $Loga^b = bLoga$

So,

$Log(0.0002) = Log(0.05^n)$ becomes

$Log(0.0002) = nLog(0.05)$

Divide both sides by $Log0.05$

$\frac{Log(0.0002)}{Log(0.05)} = \frac{nLog(0.05)}{Log(0.05)}$

$\frac{Log(0.0002)}{Log(0.05)} = n$

$n = \frac{Log(0.0002)}{Log(0.05)}$

$n = \frac{-3.69897000434}{-1.30102999566}$

$n = 2.84310893421$

$n = 3 (Approximated)$

Hence, the smallest number of servers required is 3 servers

6 0

3 years ago

To serve as a visual reminder that the structure or class name is not a variable, structure names and class names should _______

GrogVix [38]

be clearly marked as distinct from variables. Instead, they should be marked or labeled otherwise, and an explicit indication that they are not variables should be provided both next to the structure and class names, and also on a separate visual material.

7 0

4 years ago

Can you hook up an ethernet cable to a phone jack

laila [671]

The connector for ethernet cables is called RJ45. for phone jack is RJ11. Although they look the same, the RJ11 has only 4 leads, as opposed to 9 leads in RJ45. Also, RJ11 is not as wide as RJ45, so the connector does not fit.

Even if it would, the signals would be totally incompatible, so no success can be expected.

8 0

4 years ago