Answer:
The larger acute angle is equal to 50.8 degrees.
Step-by-step explanation:
Let's solve for both of the acute angles for the purpose of checking our work at the end with angle A being the top angle and angle B being the one on the base of the triangle (that's not the 90 degrees one). Determining whether to use sin/cos/tan comes from SOH-CAH-TOA.
A = cos^-1 (2√6/2√15)
However, you need to move the radical out of the denominator by multiplying √15 to the numerator and denominator. You should come up with (2√90)/30. So,
A = cos^-1 (2√90/30) = 50.768 degrees.
B = sin^-1 (2√90/30) = 39.231 degrees.
Now, we can check the work by adding the 2 angles to 90 and, if it comes to 180, it's right.
cos^-1 (2√90/30) + sin^-1 (2√90/30) + 90 = 180.
If you have any questions on where I got a formula or any step, feel free to ask in the comments!
Answer:
Ratio 1 = a(240
=b)120
=c)360
Ratio 2=a)400
=b)320
Step-by-step explanation:
On both of the ratios you first add them then divide one by one like this for example 2+1+3= 6
then 2/6 ÷720 = 120 ×2 =240 then you do this to the other numbers as well.
Answer:
its 4
Step-by-step explanation:
solve for y and then find the point of intersection
You didn’t ummm put a picture
