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svp [43]
4 years ago
7

Which expression is equivalent to 36 + 81?

Mathematics
2 answers:
KonstantinChe [14]4 years ago
8 0
The equivalent expression to 36 + 81 is 9(4 + 9).
Lostsunrise [7]4 years ago
4 0

Answer:

The answer is 9(4+9)

Step-by-step explanation:


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What is the area of this polygon? Please explain!
Anna71 [15]

to find the area, it helps to know all the lengths.

The vertical (V) piece near the 9 equals 2 and the horizontal (H) piece equals 6.

(to find the V piece, I did 10-8; for the H piece I did 15-9)

Next you have to find the area. I find its easiest to split them up into more shapes so I had a big rectangle and the little square piece at the bottom.

The measurements to multiply for the rectangle are 15*8= 120

the measurements for the little square are 9*2=18

Then you add the two numbers together 120+18=138.

The area is 138m

5 0
3 years ago
Charity sells mixed nuts over the internet. Her recipe is 9 parts peanuts to 3 parts cashews to 1 part pecans. How many pounds o
My name is Ann [436]

Answer:

45 cashews

Step-by-step explanation:

9:3:1

Add them together to get 13

195÷13= 15

15×3= 45

4 0
3 years ago
What is a 3 2/3 model example?
Annette [7]

I don't have an exact model but this site can help you.


https://learnzillion.com/lesson_plans/7928-use-models-for-division-of-fractions-by-fractions/


I hope this helps you in your studies and have an awesome day!


8 0
3 years ago
How do you solve this problem by factoring it <br><br> n^2-120=7n
eduard

hahahhgdbsnug173*;-:,@**28,-,';'*(#

4 0
4 years ago
Read 2 more answers
Can anyone help me with this?
aleksklad [387]
With the given table, this isn't possible without resorting to an approximation of an approximation.

The interval [0,8] can be partitioned as [0,2]\cup[2,4]\cup[4,6]\cup[6,8], with the respective midpoints of t\in\{1,3,5,7\}. So the average temperature is given exactly by the definite integral

\displaystyle\frac1{8-0}\int_0^8f(t)\,\mathrm dt

which is approximated by

\displaystyle\frac14\sum_{t\in\{1,3,5,7\}}f(t)=\dfrac{f(1)+f(3)+f(5)+f(7)}4

where the coefficient \dfrac14 comes from the fact that each subinterval has length 2, and so \dfrac28=\dfrac14.

However, you don't know the values of f(t) at these points. At best you can approximate them, perhaps by interpolating f(t) (you have the details needed to do it, at any rate).

Are you sure you're not supposed to find the average temperature over the entire set of observation times, i.e. over 0\le t\le16?
8 0
3 years ago
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