to find the area, it helps to know all the lengths.
The vertical (V) piece near the 9 equals 2 and the horizontal (H) piece equals 6.
(to find the V piece, I did 10-8; for the H piece I did 15-9)
Next you have to find the area. I find its easiest to split them up into more shapes so I had a big rectangle and the little square piece at the bottom.
The measurements to multiply for the rectangle are 15*8= 120
the measurements for the little square are 9*2=18
Then you add the two numbers together 120+18=138.
The area is 138m
Answer:
45 cashews
Step-by-step explanation:
9:3:1
Add them together to get 13
195÷13= 15
15×3= 45
I don't have an exact model but this site can help you.
https://learnzillion.com/lesson_plans/7928-use-models-for-division-of-fractions-by-fractions/
I hope this helps you in your studies and have an awesome day!
hahahhgdbsnug173*;-:,@**28,-,';'*(#
With the given table, this isn't possible without resorting to an approximation of an approximation.
The interval
![[0,8]](https://tex.z-dn.net/?f=%5B0%2C8%5D)
can be partitioned as
![[0,2]\cup[2,4]\cup[4,6]\cup[6,8]](https://tex.z-dn.net/?f=%5B0%2C2%5D%5Ccup%5B2%2C4%5D%5Ccup%5B4%2C6%5D%5Ccup%5B6%2C8%5D)
, with the respective midpoints of

. So the average temperature is given exactly by the definite integral

which is approximated by

where the coefficient

comes from the fact that each subinterval has length 2, and so

.
However, you don't know the values of

at these points. At best you can approximate them, perhaps by interpolating

(you have the details needed to do it, at any rate).
Are you sure you're not supposed to find the average temperature over the entire set of observation times, i.e. over

?