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seropon [69]
3 years ago
14

"If triangle vuw is equiangular, find k and t

Mathematics
2 answers:
alekssr [168]3 years ago
7 0
The answer is b. k=64 t=52

pishuonlain [190]3 years ago
6 0

It says B k=64, t=52 is wrong

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There are 110 calories per 28.4 grams of Cereal X. Find how many calories are in 39.76 grams of Cereal X
malfutka [58]

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Step-by-step explanation:

2. Find the area of the parallelogram.

A.38cm

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3 0
3 years ago
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Draw a tape diagram to represent 3+5-5=3
xxTIMURxx [149]

Answer:

i will have to draw it for you

Step-by-step explanation:

the reason why there is an X on the 5 squares is because you added then subtracted them

8 0
3 years ago
When the expression $-2x^2-20x-53$ is written in the form $a(x+d)^2+e$, where $a$, $d$, and $e$ are constants, then what is the
Sladkaya [172]
We start with 2 x^{2} -20x-53 and wish to write it as a(x+d) ^{2} +e

First, pull 2 out from the first two terms: 2( x^{2} -10x)-53

Let’s look at what is in parenthesis. In the final form this needs to be a perfect square. Right now we have x^{2} -10x and we can obtain -10x by adding -5x and -5x. That is, we can build the following perfect square: x^{2} -10x+25=(x-5) ^{2}

The “problem” with what we just did is that we added to what was given. Let’s put the expression together. We have 2( x-5) ^{2}-53 and when we multiply that out it does not give us what we started with. It gives us 2 x^{2} -20x+50-53=2 x^{2} -20x-3

So you see our expression is not right. It should have a -53 but instead has a -3. So to correct it we need to subtract another 50.

We do this as follows: 2(x-5) ^{2}-53-50 which gives us the final expression we seek:

2(x-5) ^{2}-103

If you multiply this out you will get the exact expression we were given. This means that:
a = 2
d = -5
e =  -103

We are asked for the sum of a, d and e which is 2 + (-5) + (-103) = -106


7 0
3 years ago
Is 1/2 (8 - 4g) equivalent to 4 + 2g?
Crazy boy [7]

Answer:

no

1/2 (8 - 4g) is 4 - 2g

4 - 2g doesn't equal 4 + 2g

7 0
2 years ago
This question relates to concepts covered in Lectures 1 & 2. You can use any of the excel files posted to work through the q
liubo4ka [24]

Answer:

mean of this demand distribution = 100

Step-by-step explanation:

To find the mean of this demand distribution;

Mean = Expected vale = E[x]

for discrete provability function,

we say E[x] = ∑(x.p(x))

x     p(x)     x.p(x)

10     0.1     1

30    0.4    12

60    0.4    24

90    0.7    63

∴ ∑(x.p(x)) = ( 1 + 12 + 24 + 63 )

∑(x.p(x)) = 100

7 0
3 years ago
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