Question

A plumber charge $50 each visit plus $15 per hour how many hours did the plumber work if he charged a total of $110 Create an equation and solve for the number of hours the plumber worked

Answer 1

Plumber's total charge: C(x) = $50 + ($15/hr)x, where x is the # of hours worked.

Setting C(x) = $110, we have $110 = $50 + ($15/hr)x

Subtracting $50 from both sides results in $60 = ($15/hr)x, which comes

out to x = 4. The plumber worked for 4 hours to earn $110.

Answer 2

since the initial fee is $50, and every hour is $15, if h is equal to hour, the equation would be like this:

50 + 15h = 110.

Then, if we want to get the answer, we need to solve the equation.

First we pass the 50 to the other side, like this:

15h = 110 - 50

15h = 60

Then we pass the 15 dividing like this:

h = 60/15

h = 4

And we get four!

So the answer is: 4.

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