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Sergio039 [100]
3 years ago
12

Need help please asap due 5:30​

Mathematics
1 answer:
notsponge [240]3 years ago
3 0

Answer:

5 30 is my guess

Step-by-step explanation:

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Carolyn and Joyce ordered a large pizza that had 12 slices. Carolyn ate 1
kondor19780726 [428]

Answer:

They ate \frac{1}{3} of the pizza

Step-by-step explanation:

Carolyn and Joyce at 4 slices of pizza altogether, and since there are 12 slices of pizza, they ate \frac{4}{12}=\frac{1}{3} of the pizza.

5 0
2 years ago
A retangle has a perimeter (p) of 58 inches. The length (L) is one more than 3 times the width (W)
worty [1.4K]

The rectangle has a perimeter P of 58 inches.The length l is one more than 3 times the width w.write and solve a system of linear equations to find the length and width of the rectangle?

Answer:

Length(L)=22 inches

Width(W) = 7 inches

Step-by-step explanation:

GIven:-

Perimeter (p)=58 inches,

Length(L)= one more than 3 times the width(W)

Let, W=x   ---------------------------------(equation 1

L=3x+1  -----------------------(equation 2)

Here x is unknown and to find the Width(W) we have to find the value of x.

Now,

Perimeter of rectangle(p) = 2 times length(L) + 2 times width(W)

p=2L+2W

p=2(3x+1)+2x  ----------------(from equation 1)

58=6x+2+2x   ----------------(given p=58 inches)

58=8x+2

8x=58-2

8x=56

x=\frac{56}{8}

x=7          ----------------------(equation 3)

Now substituting the value of equation 3 in equation 2.

L=3x+1

L=(3\times 7)+1

L=21+1

L=22

L=22 inches

as, W=x   -----------------------(from equation 1)

W=7 inches -------------------(equation 3)

Therefore, Length(L) = 22 inches and Width(W) = 7 inches.

7 0
3 years ago
Please help ♡♡♡♡♡♡♡​
lions [1.4K]

Step-by-step explanation:

\angle AOB and \angle BOC are linear pair angles.

\therefore m\angle AOB + m\angle BOC = 180° \\  \therefore  \: 3x + 124 \degree + 6x + 29 \degree  = 180° \\  \therefore  \: 9x  + 153 \degree  = 180°  \\ \therefore  \: 9x  = 180°  - 153 \degree   \\ \therefore  \: 9x  = 27 \degree   \\ \therefore  \:x =  \frac{27 \degree }{9}  \\  \huge \pink{ \boxed{\therefore  \:x =3 \degree }} \\  \\  \because \: m\angle BOC =6x + 29 \degree   \\ \therefore \: m\angle BOC =6 \times3 \degree + 29 \degree   \\ \therefore \: m\angle BOC = 18\degree + 29 \degree    \\ \\   \huge \red{ \boxed{\therefore \: m\angle BOC = 47 \degree   }}

5 0
3 years ago
I don’t know how to do this
stich3 [128]

To check for continuity at the edges of each piece, you need to consider the limit as x approaches the edges. For example,

g(x)=\begin{cases}2x+5&\text{for }x\le-3\\x^2-10&\text{for }x>-3\end{cases}

has two pieces, 2x+5 and x^2-10, both of which are continuous by themselves on the provided intervals. In order for g to be continuous everywhere, we need to have

\displaystyle\lim_{x\to-3^-}g(x)=\lim_{x\to-3^+}g(x)=g(-3)

By definition of g, we have g(-3)=2(-3)+5=-1, and the limits are

\displaystyle\lim_{x\to-3^-}g(x)=\lim_{x\to-3}(2x+5)=-1

\displaystyle\lim_{x\to-3^+}g(x)=\lim_{x\to-3}(x^2-10)=-1

The limits match, so g is continuous.

For the others: Each of the individual pieces of f,h are continuous functions on their domains, so you just need to check the value of each piece at the edge of each subinterval.

4 0
3 years ago
Plsssssssssssssssshelppppppppppppppppppppppppppppppppppppp
tino4ka555 [31]

ummmmmmmmmmmmmmmmmmmmmmmmmm?mmmmmmmmmmmmmmmm?mmmmmmmmmmmmm withhhhhhhhhhhhhhhhh whatttttttttttttttttt

4 0
2 years ago
Read 2 more answers
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