For this case, the first thing we must do is find the scale factor.
For this, we use one of the dimensions. We will use the width of the photo.
We have then:
![k = \frac {132} {11}\\k = 12](https://tex.z-dn.net/?f=k%20%3D%20%5Cfrac%20%7B132%7D%20%7B11%7D%5C%5Ck%20%3D%2012)
Then, we look for the value of the height of the new photo. To do this, we multiply the scale factor by the original dimension.
We have then:
![14k = 14 (12) = 168](https://tex.z-dn.net/?f=14k%20%3D%2014%20%2812%29%20%3D%20168)
Answer:
the new height will be:
d.168 inches
F(x) = k(x+2)(2x-1)(x-3), where k is some constant
= k(2x^3-3x^2-11x+6)
= k(-2x^3+3x^2+11x-6)
k defines some vertical stretch, so there are an infinitely many solutions for f(x).
This is simple proportions, because of their similarity:
![\frac{13}{38.6} = \frac{10}{x}](https://tex.z-dn.net/?f=%20%5Cfrac%7B13%7D%7B38.6%7D%20%3D%20%5Cfrac%7B10%7D%7Bx%7D%20)
The length of GE is 10 units
Explanation:
Given that the length of XY = 5 units and YZ = 4.6 units
<u>The length of GE:</u>
We need to determine the length of GE
From the figure, we can see that ZY bisects GE and XY bisects EF.
The lines ZY and XY both bisect GF.
The midpoint theorem states that "the line segment connecting the midpoints of two sides of a triangle is parallel to the third side and is congruent to one half of the third side".
Since, we have,
EX = XF and X is the midpoint of EF
GY = YF and Y is the midpoint of GF
Since, XY is the line segment that connects the midpoints of the two sides of the triangle.
Applying the midpoint theorem, we have,
![GE = 2XY](https://tex.z-dn.net/?f=GE%20%3D%202XY)
![GE = 2(5)=10 \ units](https://tex.z-dn.net/?f=GE%20%3D%202%285%29%3D10%20%5C%20units)
Thus, the length of GE is 10 units.