Answer:
2x+30
Step-by-step explanation:
The perimeter of a rectangle is
P = 2(l+w)
The length is 2/3 x+10 and the width is 1/3x +5
P = 2(2/3x +10 + 1/3x +5)
Combine like terms
P = 2(2/3x + 1/3x +10+5)
= 2(x +15)
Distribute the 2
= 2x+30
Thank you for posting your question here at brainly. Below ist he answers:
a. T= d/r
b. It's reasonable to write distance as a positive number because distance is always positive. You are not able to have a negative distance. Imagine someone standing on a side walk. Even if they are not moving, their distance is 0 which is positive. If they move backwards or forwards, their distance is still positive because it is more than that 0 and they are gaining something.
c. T= d/r
T= 32.12 m /<span>8.8 m/min
T= 3.65 min
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Answer:
The two integers are 23 and 12
Step-by-step explanation:
Let the two integers be f and g
Let f be the biggest and g the smallest integer
From the first statement, the sum of the two integers is 35 i.e
f + g = 35. (1)
From second statement, we were told that when the smaller integer is subtracted from twice the larger, the result is 34 i.e
2f — g = 34. (2)
Now we'll solve by elimination method as follows:
Add equation (2) and (1) together:
2f — g = 34
+ f + g = 35
3f = 69
Divide both side by the coefficient of f i.e 3
f = 69/3
f = 23
Substituting the value of f into equation(1)
f + g = 35
23 + g = 35
Collect like terms
g = 35 — 23
g = 12
The two integers are 23 and 12
The Cartesian product of two sets can be defined as the following: the set of all possible pairs where the 1st coordinate is an element of the 1st set and the 2nd coordinate is the element of the 2nd set. This has an obvious generalization for n sets (the cartesian product has then n coordinates).
Let us pick now all the pairs that have 100 as their first coordinate. We then have 2 choices for the 2nd coordinate, 1 and 2. Hence, the 2 pairs are: (100,1), (100,2). Similarly, if 200 is the first coordinate, the pairs are (200,1), (200,2).
These 4 pairs are the cartesian product (we have 4 pairs =2 elements from X* 2 elements from Y) .
It helps to remember that the cartesian product has as many elements as the product of the number of elements of each set.
Answer:
10.14 feet per year.
Step-by-step explanation:
Given:
Over the next 3 1/2 years, a tree grew to a final height of 35 1/2 feet.
Question asked:
During those 3 1/2 years, what was the average yearly growth rate of the height of the tree?
Solution:
We can find the average yearly growth rate by using average formula, taking
final height of the tree as sum of observation and time span taken to growth as number of observation:-
As we know:
Thus, during 
, the average yearly growth rate of the height of the tree was 10.14 feet per year
