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svet-max [94.6K]
3 years ago
14

. The table lists the number of students from Windy Brook Middle School at the state fair. What is the ratio of sixth graders to

the total number of students at the fair?
Mathematics
1 answer:
Olin [163]3 years ago
5 0

Answer:im so sorry these people wasted your time hun Answer:

2 : 9

Step-by-step explanation:

First find the total number

6+4+5+3 = 18

6th graders : total

4 : 18

Divide each side by 2

4/2: 18/2

2 : 9

there ya go!

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Find the area of the shaded region. Round your answer to the nearest TENTH.​
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3 years ago
Use the PACED decision-making process to _____.
Alex_Xolod [135]
Use the PACED decision-making process to make a decision or make a choice. The steps to follow when making a decision can be easily remembered when you use the word PACED:
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6 0
3 years ago
One step inequalities.... 9x&lt;18<br> how to solve
Nuetrik [128]
So 9x<18 can be factored out into 
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5 0
3 years ago
Read 2 more answers
Question in picture<br><br>A) 16/63<br><br>B)-16/63<br><br>C) 63/16<br><br>D) -63/16
Orlov [11]
ANSWER
\tan(x + y) =  -  \frac{63}{16}


EXPLANATION


We were given that,

\csc(x)  =  \frac{5}{3}

This implies that,

\sin(x)  =  \frac{3}{5}

We use the Pythagorean identity

\sin^{2} (x)  +  \cos^{2} (x)= 1
to get,


\cos(x)  =  \sqrt{1 - ( { \frac{3}{5} })^{2}}  =  \frac{4}{5}


We were also given that,


\cos(y)  =  \frac{5}{13}

This means that,


\sin(y)  =  \sqrt{1 -  {( \frac{5}{13}) }^{2} }  =  \frac{12}{13}

This is because,


0 <  \: x \:  <  \frac{\pi}{2}


0 <  \: y \:  <  \frac{\pi}{2}

This angles are in the first quadrant so we pick the positive values.

\tan(x + y)  =  \frac{ \sin(x + y) }{ \cos(x + y) }


\tan(x + y)  =  \frac{ \sin(x ) \cos(y)   +  \sin(y)  \cos(x) }{ \cos(x) \cos(y)  -  \sin(x)  \sin(y) }



\tan(x + y)  =  \frac{  \frac{3}{5}   \times  \frac{5}{13}  +   \frac{12}{13}   \times  \frac{4}{5}  }{  \frac{4}{5}  \times  \frac{5}{13}   -   \frac{3}{5}  \times  \frac{12}{13}  }



\tan(x + y) =  -  \frac{63}{16}

The correct answer is D
4 0
3 years ago
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