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Maslowich
4 years ago
12

How do I substitute this?

Mathematics
1 answer:
Lemur [1.5K]4 years ago
7 0

You want to isolate one of the variables (x or y) so you can plug it into the other equation. The easiest one is isolating the 2nd equation.

3x² - 16x + 13 - y = 0   Add y on both sides

3x² - 16x + 13 = y

You can use this and plug it into the first equation

y - 12x + 15 = 3x²

(3x² - 16x + 13) - 12x + 15 = 3x²

3x² - 16x + 13 - 12x + 15 = 3x²  Combine like terms

3x² - 28x + 28 = 3x²  Subtract 3x² on both sides

-28x + 28 = 0  Add 28x on both sides

28 = 28x Divide 28 on both sides

1 = x

Now that you know x, you can plug it into either of the equation to find y

3(1)² - 16(1) + 13 - y = 0

3 - 16 + 13 - y = 0

-y = 0 Divide -1 on both sides

y = 0


x = 1, y = 0

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Which is perpendicular to the line y=-3x-8y
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740

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Given a₃ = 7 and a₇ = (3 × 7) + 2 = 21 + 2 = 23 , then

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