Answer:
B
Step-by-step explanation:
so from 190.1 to 201.5 is 201.5 - 190.1 = 11.4.
now, if we take 190.1 as the 100%, what is 11.4 off of it in percentage?
![\bf \begin{array}{ccll} amount&\%\\ \cline{1-2} 190.1&100\\ 11.4&x \end{array}\implies \cfrac{190.1}{11.4}=\cfrac{100}{x}\implies 190.1x=1140 \\\\\\ x=\cfrac{1140}{190.1}\implies x\approx 5.99684](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7Bccll%7D%20amount%26%5C%25%5C%5C%20%5Ccline%7B1-2%7D%20190.1%26100%5C%5C%2011.4%26x%20%5Cend%7Barray%7D%5Cimplies%20%5Ccfrac%7B190.1%7D%7B11.4%7D%3D%5Ccfrac%7B100%7D%7Bx%7D%5Cimplies%20190.1x%3D1140%20%5C%5C%5C%5C%5C%5C%20x%3D%5Ccfrac%7B1140%7D%7B190.1%7D%5Cimplies%20x%5Capprox%205.99684)
Answer:
E(w) = 1600000
v(w) = 240000
Step-by-step explanation:
given data
sequence = 1 million iid (+1 and +2)
probability of transmitting a +1 = 0.4
solution
sequence will be here as
P{Xi = k } = 0.4 for k = +1
0.6 for k = +2
and define is
x1 + x2 + ................ + X1000000
so for expected value for W
E(w) = E( x1 + x2 + ................ + X1000000 ) ......................1
as per the linear probability of expectation
E(w) = 1000000 ( 0.4 × 1 + 0.6 × 2)
E(w) = 1600000
and
for variance of W
v(w) = V ( x1 + x2 + ................ + X1000000 ) ..........................2
v(w) = V x1 + V x2 + ................ + V X1000000
here also same as that xi are i.e d so cov(xi, xj ) = 0 and i ≠ j
so
v(w) = 1000000 ( v(x) )
v(w) = 1000000 ( 0.24)
v(w) = 240000
Answer:
$720 in one week
Step-by-step explanation:
40 * 18
$720
Best of Luck!