Exactly right down to the last step, but some errors in combining terms.
(6m^5 + 3 – m^3 – 4m) – (–m^5 + 2m^3 – 4m + 6)
= (6m^5 + 3 – m^3 – 4m) + (m^5 – 2m^3 + 4m – 6)
= 6m^5 + 3 + (–m^3) + (–4m) + m^5 + (–2m^3) + 4m + (–6)
= [6m^5 + m^5] + [3 + (–6)] + [(–m^3) + (–2m^3)] + [(–4m) + 4m]
= (6+1)m^5 +(-1-2)m^3 +(-4+4)m +(3-6)
= 7m^5 – 3m^3 – 3
Answer:
my big brother had the same question so ill ask him to help u
Step-by-step explanation:
Answer:
The total of Charlie's be $7.
Step-by-step explanation:
Given:
Charlie and his friend Jay went to the fair. They were having a sale and the admission was 25% off.
The regular ticket price was $9.00.
And the tax is 6%.
Now, to find Charlie’s total.
So ,we deduct the 25% off first:
Now, including tax :
<u><em>Approximately = $7.</em></u>
Therefore, the total of Charlie's be $7.
Answer:
-8
Step-by-step explanation:
Answer:
The number of students bringing lunch from home are 99 students
Step-by-step explanation:
1/5 = .2
.2*495=99
