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4 years ago

14

What is the percentage of error in weight if measured weight is 22 pounds and actual weight is 25 pounds

1 answer:

IRISSAK [1]4 years ago

7 0

The percent error is by 12%

<span>The percent error is calculated by subracting the actual weight from the estimated weight and then dividing it by the actual value and multiplying it by 100% in absolute value(Which means to remove any negative sign) </span>

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Inessa05 [86]

Answer: $(0.771,\ 0.829)$

Step-by-step explanation:

Given : Significance level : $\alpha: 1-0.99=0.01$

Critical value : $z_{\alpha/2}=2.576$

Sample size : n=1305

The proportion of tenth graders read above the eighth grade level. = $p=\dfrac{1044}{1305}=0.8$

The confidence interval for population proportion is given by :-

$p\pm z_{\alpha/2}\sqrt{\dfrac{p(1-p)}{n}}\\\\=0.8\pm(2.576)\sqrt{\dfrac{0.8(1-0.8)}{1305}}\\\\\approx0.8\pm0.029\\\\=(0.771,\ 0.829)$

Hence, the 99% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.771,0.829) .

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Mariana [72]

13 is what i think
3 divided by 2= 1.5
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