Answer:
(2,1)
Step by step explanation:
Please find the attachment.
We have been given that line 
is horizontal and passes through point (1,1). Line 
is vertical and passes through point (2,2). We are asked to find point of intersection of line and line .
Line is a horizontal line so y-coordinate will be 1 for any value of x. Line is a vertical line, so x-coordinate will be 2 for any value of y.
Therefore, intersection point of both lines will include x-coordinate of line and y-coordinate of line that is (2,1).
Answer:
Actual volume=3,773,000 in³
Step-by-step explanation:
Scale 1:35
Actual Width=Model Width×Scale factor=(2×35)=70 inches
Actual Length=Model Length×Scale factor=(11×35)=385 inches
Actual Height=Model Height×Scale factor=(4×35)=140 inches
Actual volume =(Base Area×Height)=Length×width×height=(385×70×140)=3,773,000 in³
Actual volume=3,773,000 in³
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If I read the question correctly, the information about the 80x80 fencing and the grass region are all irrelevant information.
In order to find the area of the side walk we are going to use the formula A=pi(r^2) where r = the radius. The diameter of the pool is 60 feet and the the sidewalk is 5 feet bigger all around meaning we had 5 feet to both sides of this 60 feet giving you an overall diameter of 70 feet (or 60 + 5*2). To find the radius take half of the diameter. 70/2 = 35.
Now we plug in 35 to the equation. A = Pi(35^2) = 1225pi. Leave your answer like this as we are not finished and will need to round at the end for an accurate answer. This is NOT the end, that number is the area of the sidewalk AND the pool.
The sidewalk is not a full circle, just a border so we now have to find the area of the actual pool and subtract it from this 1225pi for the sidewalk's area. Same formula, Area = pi(r^2). The diameter of the pool is 60 meaning the radius is 30 (or 60/2). Plug into the equation, pi(30^2) = 900pi.
Now do 1225pi - 900pi to get 325pi. Break out your calculator and hit the approximation button. 325pi is approximately 1021.018 if rounded to 3 decimal places.
The area of the 5-foot wide sidewalk encircling the pool is approximately 1021.018 square feet.
Answer:
-512
Step-by-step explanation:
