Answer:
int count =0;
for(int i=0;i<10;i++)
{
if(myArray[i]>=0)
{
count++;
}
}
cout<<"Number of positive integers is "<<count<<endl;
Explanation:
The above written loop is for counting positive integers in the myArray[].
For counting we have taken a count integer initialized with 0.On iterating over the array if the element is greater than or equal to 0 we consider it as positive and increasing the count.At the end printing the count.
Answer:
Websphere Studio Application Developer
Answer:
A communication barrier is anything that prevents us from receiving and understanding the messages others use to convey their information, ideas and thoughts.They can interfere with or block the message you are trying to send.
Answer:
3,265,920 unique ID exist.
Explanation:
The nine digits are from 0 to 9, there are ten bits from 0 -9,
0, 1, 2, 3, 4, 5, 6, 7, 8, 9
The first is select from the highest bit (9), and the second is selected at random from 0 - 9, the third bit to the last must be unique and different from each other;
number of unique IDs = 9 × 9 × 8 × 7 × 6 × 5 × 4 × 3 × 2
Multiplying the nine bits of unique IDs = 3,265,920.
Answer:
50
var X gets passed into the rectangle function, which I assume would set the x and y coordinates to what the var's have already been set to.