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satela [25.4K]
2 years ago
15

Write a program to change background colour of your visual basic form with any 3 different events.​

Computers and Technology
2 answers:
Stels [109]2 years ago
4 0

Answer:

To change the background color, select the form in Visual Studio and locate the BackColor property in the Properties panel. There are a number of ways to specify a color. Color by name - Simply type in a color name into the BackColor value field (for example Red, Yellow, Cyan etc).

Explanation:

klemol [59]2 years ago
4 0

Answer:

To change the background color, select the form in Visual Studio and locate the BackColor property in the Properties panel. There are a number of ways to specify a color. Color by name - Simply type in a color name into the BackColor value field (for example Red, Yellow, Cyan etc)

Explanation:

You might be interested in
3.6 Code Practice on Edhesive
Alchen [17]

I've included my code in the picture below. Best of luck.

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2 years ago
Which is a common problem caused by the widespread use of computers?
Andru [333]
Hacking would be a widespread problem.
8 0
3 years ago
2) [13 points] You’ve been hired by Banker Bisons to write a C++ console application that determines the number of months to rep
Paha777 [63]

Answer:

Check the explanation

Explanation:

CODE:

#include <iostream>

#include <iomanip>

using namespace std;

double getLoanAmount() { // functions as per asked in question

double loan;

while(true){ // while loop is used to re prompt

cout << "Enter the car loan amount ($2,500-7,500): ";

cin >> loan;

if (loan>=2500 && loan <= 7500){ // if the condition is fulfilled then

break; // break statement is use to come out of while loop

}

else{ // else error message is printed

cout << "Error: $"<< loan << " is an invalid loan amount." << endl;

}

}

return loan;

}

double getMonthlyPayment(){ // functions as per asked in question

double monthpay;

while(true){ // while loop is used to re prompt

cout << "Enter the monthly payment ($50-750): ";

cin >> monthpay;

if (monthpay>=50 && monthpay <= 750){ // if the condition is fulfilled then

break; // break statement is use to come out of while loop

}

else{ // else error message is printed

cout << "Error: $"<< monthpay << " is an invalid monthly payment." << endl;

}

}

return monthpay;

}

double getInterestRate(){ // functions as per asked in question

double rate;

while(true){ // while loop is used to re prompt

cout << "Enter the annual interest rate (1-6%): ";

cin >> rate;

if (rate>=1 && rate <= 6){ // if the condition is fulfilled then

break; // break statement is use to come out of while loop

}

else{ // else error message is printed

cout << "Error: "<< rate << "% is an invalid annual interest rate." << endl;

}

}

return rate;

}

int main() {

cout << setprecision(2) << fixed; // to print with 2 decimal places

int month = 0; // initializing month

// calling functions and storing the returned value

double balance= getLoanAmount();

double payment= getMonthlyPayment();

double rate= getInterestRate();

rate = rate /12 /100; // as per question

// printing as per required in question

cout << "Month Balance($) Payment($) Interest($) Principal($)"<< endl;

while(balance>0){ // while the balance is more than zero

month = month + 1; // counting Months

// calculations as per questions

double interest = balance * rate;

double principal = payment - interest;

balance = balance - principal;

// printing required info with proper spacing

cout <<" "<< month;

cout <<" "<< balance;

cout <<" "<< payment;

cout <<" "<< interest;

cout <<" "<< principal << endl;

}

cout << "Months to repay loan: " << month << endl; // displaying month

cout << "End of Banker Bisons";

Kindly check the output in the attached image below.

5 0
3 years ago
Write a function: function solution(N); that, given a positive integer N, prints the consecutive numbers from 1 to N, each on a
koban [17]

Answer:

<em>The program written in Python is as follows:</em>

def solution(N):

     concat = ""

     for i in range(1,N+1):

           if not(i%2 == 0 or i%3 ==0 or i%5 == 0):

                 print(str(i))

           else:

                 if i%2 == 0:

                       concat= concat+"Codility"

                 if i%3 == 0:

                       concat= concat+"Testers"

                 if i%5 == 0:

                       concat= concat+"Coders"

                 print(concat)

                 concat = ""

N = int(input("Enter a positive integer: "))

solution(N)

Explanation:

This line declares the function

def solution(N):

This line initializes a variable named concat to an empty string

     concat = ""

This line iterates from 1 to the input integer

     for i in range(1,N+1):

<em>This line checks if the current number of iteration is divisible by 2,3 or 5, if no, the number is printed</em>

           if not(i%2 == 0 or i%3 ==0 or i%5 == 0):

                 print(str(i))

<em>If otherwise</em>

           else:

<em>This lines checks if current number is divisible by 2; if yes the string "Codility" is concatenated to string concat</em>

                 if i%2 == 0:

                       concat= concat+"Codility"

<em>This lines checks if current number is divisible by 3; if yes the string "Testers" is concatenated to string concat</em>

<em>                 </em> if i%3 == 0:

                       concat= concat+"Testers"

<em>This lines checks if current number is divisible by 2; if yes the string "Coders" is concatenated to string concat</em>

                 if i%5 == 0:

                       concat= concat+"Coders"

<em>The concatenated string is printed using this line</em>

                 print(concat)

This variable concat is intialized back to an empty string

                 concat = ""

The main method starts here

N = int(input("Enter a positive integer: "))

This line calls the defined function solution

solution(N)

6 0
3 years ago
Which of the following computer component facilitates internet connection?
babunello [35]

Answer:

your answer may be(utility software)

8 0
2 years ago
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