Given two points (x₁,y₁) and (x₂,y₂) the midpoint would be:
M=((x₁+x₂)/2 , (y₁+y₂)/2)

In this case, the points would be: (-8,-7) and (-7,-8); therefore:
M=((-8-7)/2 , (-7-8)/2)=(-15/2,-15/2)

Answer: C.) (-15/2 , -15,2)

6 0

3 years ago

Need help its sector area

Paladinen [302]

Area of sector

$= \frac{30}{360} \times \pi \times {(radius)}^{2}$

$= \frac{30}{360} \times \ \frac{22}{7} \times {(12)}^{2}$

$= \frac{30}{360} \times \ \frac{22}{7} \times 12 \times 12$

so the area = 37.71 square metre

8 0

3 years ago

a right triangle has legs of length 3x m and 4x m and hypotenuse of length 75 m. find the lengths of the legs of the triangle

just olya [345]

It is a 3-4-5 right triangle

leg1 := 3x, leg2:=4x, hypotenuse:=5x

given hypotenuse = 75m
=> 5x=75
So, x= 75÷5 = 15
Therefore, leg1 = 3(15) = 45m.
leg2= 4(15) = 60m.

4 0

3 years ago

find two consecutive odd numbers such that the sum of the larger number and twice the smaller number is 27 less then four times

soldier1979 [14.2K]

N is an odd integer

The Next Larger is N+2

N+2 + 2N = -27 + 4N

3N + 2 = 4N - 27

0 = 4N - 27 - 3N - 2

0 = N - 29

N = 29

They are 29 and 31.

31 + 2(29) = 4(29) - 27

31 + 58 = 89 = 116 - 27 yes it works

4 0

3 years ago