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4 years ago

What is 39/51 in simplest form?

Mathematics

2 answers:

liq [111]4 years ago

8 0

13/17 if you are trying to simplify it. You divide it by 3 on the top and bottom

marshall27 [118]4 years ago

5 0

13/17, hope I helped please hit that thank you button!

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Two adjacent, supplementary angles form a<br><br> line?

omeli [17]

obtuse because it all adds up to 180 degrees

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3 years ago

This cake was sliced diagonally.What shape will the cross-section make?

marta [7]

If you were to cut a cake diagonally we could say the result would be an oval. Please refer to the image I provided below.

7 0

3 years ago

Read 2 more answers

2(v–11) please help me solve this

nika2105 [10]

Answer: 2v-22

Step-by-step explanation:

2(v)=2v

2(-11)= -22

2v - 22

6 0

3 years ago

From a random sample of 58 businesses, it is found that the mean time the owner spends on administrative issues each week is 21.

zzz [600]

Answer: (20.86, 22.52)

Step-by-step explanation:

Formula to find the confidence interval for population mean :-

$\overline{x}\pm z^*\dfrac{\sigma}{\sqrt{n}}$

, where $\overline{x}$ = sample mean.

z*= critical z-value

n= sample size.

$\sigma$ = Population standard deviation.

By considering the given question , we have

$\overline{x}= 21.69$

$\sigma=3.23$

n= 58

Using z-table, the critical z-value for 95% confidence = z* = 1.96

Then, 95% confidence interval for the amount of time spent on administrative issues will be :

$21.69\pm (1.96)\dfrac{3.23}{\sqrt{58}}$

$=21.69\pm (1.96)\dfrac{1.7}{7.61577}$

$=21.69\pm (1.96)(0.223221)$

$\approx21.69\pm0.83$

$=(21.69-0.83,\ 21.69+0.83)=(20.86,\ 22.52)$

Hence, the 95% confidence interval for the amount of time spent on administrative issues = (20.86, 22.52)

7 0

3 years ago

Numbers are (-20,10) and (40,-50)

seropon [69]

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6 0

3 years ago