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AlladinOne [14]
3 years ago
6

A​ cone-shaped paper water cup has a height of 12 cm and a radius of 6 cm. If the cup is filled with water to five dash sixths i

ts​ height, what portion of the volume of the cup is filled with​ water?
Mathematics
1 answer:
s2008m [1.1K]3 years ago
8 0

Answer:

125/216 or (5/6)³

Step-by-step explanation:

height of water column=5/6 ×12=10 cm

radius of water level=10/12×6=5 cm

volume of water=π ×5²×10=250 π cm³

volume of cone=π×6²×12=432 π cm³

reqd. ratio=250 π/432 π=125/216=(5/6)³

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⦁ Show (2.3)(5.06) as a fraction multiplication problem and explain why the answer is in thousandths (three decimal places). 
astra-53 [7]

we have

(2.3)(5.06)

we know that

2.3=\frac{23}{10}

5.06=\frac{506}{100}

so

(2.3)(5.06)=(\frac{23}{10})(\frac{506}{100})

=\frac{11,638}{1,000}

=11.638

the answer is in thousandths, because the denominator of the multiplication of the two fractions is one thousand

8 0
3 years ago
Read 2 more answers
Solve for ppp. -5\left(p+\dfrac35\right) = -4−5(p+ 5 3 ​ )=−4minus, 5, left parenthesis, p, plus, start fraction, 3, divided by,
Angelina_Jolie [31]

Answer:

p = 1

Step-by-step explanation:

4 - 5(p + 3/5) = -4

Find P

4 - 5(p + 3/5) = -4

4 - 5p -15/5 = -4

4 - 5p - 3 = -4

-5p + 1 = -4

-5p = -4 - 1

-5p = -5

p = -5/-5

p = 1

Check:

4 - 5(p + 3/5) = -4

4 - 5(1 + 3/5) = -4

4 - 5 - 15/5 = -4

4 - 5 - 3 = -4

4 - 8 = -4

-4 = -4

8 0
3 years ago
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An instructor wants to write a test with 25 questions where each question is worth 3, 4, or 5 points based on difficulty. He wan
irakobra [83]

ANSWER

Find out the how many 3, 4, and 5 point questions could there be.

To proof

Let us assume that the 3 points based question be = x

Let us assume that the 4 points based question be = y

Let us assume that the 5 points based question be = z

As given

An instructor wants to write a test with 25 questions

than the equation become in the form

x + y + z = 25

he quiz to be worth a total of 100 points.

than the equation is becomes

3x + 4y + 5z =100

As given

He wants the number of 3-point questions to be 4 less than the number of 4-point questions

x = y -4

Than the three equation are

x + y + z = 25 ,3x + 4y + 5z =100 and x = y -4

put  x = y -4 in the x + y + z = 25 ,3x + 4y + 5z =100

than

2y + z = 29, 7y +5z= 112

multiply 2y + z = 29 by 5 and subtracted 7y +5z= 112

10 y -7y + 5y -5y = 145 -112

3y = 33

y = \frac{33}{3}

y =11

put in the  x = y -4

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put the value of x ,y in the x + y + z = 25

7 + 11 +z =25

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z = 25 -18

z=7

therefore

numbers of the 3 point question be = 7

numbers of the 4 point question be = 11

numbers of the 5 point question be = 7

Hence proved



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