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AlexFokin [52]
3 years ago
5

Help Pleaseeee. Find the hypotenuse.

Mathematics
1 answer:
ivann1987 [24]3 years ago
8 0

I don't because I can't see

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If angle B measures 120 degrees, find
SpyIntel [72]

Answer:

C. 120°

Step-by-step explanation:

There are two paralell lines, one is part of Angle B, and the other of Angle Q. Then there is a diagonal line, coming at the same angle from B all the way to Q, because the other two lines are paralell. It basically means if you were to slide the flat line which is connected to Q up the diagonal line, it would fit perfectly with it's parallel. So the two angles; Angle B and Angle Q; are the exact same.

Hope this helped! Good luck with future math problems :)

7 0
4 years ago
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What ratios are equivalent to 2 : 7?
vaieri [72.5K]

Answer:

4:14, 6:21, 8:28

Step-by-step explanation:

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3 years ago
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Factor the following and find the zeros.
yaroslaw [1]
1.\ x^2-169=0\\\\x^2-13^2=0\\\\(x-13)(x+13)=0\iff x=13\ \vee\ x=-13

2.\ x^2+14x+49=0\\\\x^2+2x\cdot7+7^2=0\\\\(x+7)^2=0\\\\(x+7)(x+7)=0\iff x=-7

3.\ x^2-17x+42=0\\\\x^2-14x-3x+42=0\\\\x(x-14)-3(x-14)=0\\\\(x-14)(x-3)=0\iff x=14\ \vee\ x=3

4.\ 2x^2-9x-5=0\\\\2x^2-10x+x-5=0\\\\2x(x-5)+1(x-5)=0\\\\(x-5)(2x+1)=0\iffx=5\ \vee\ x=-\frac{1}{2}

5.\ 3x^2+11x-4=0\\\\3x^2+12x-x-4=0\\\\3x(x+4)-1(x+4)=0\\\\(x+4)(3x-1)=0\iff x=-4\ \vee\ x=\frac{1}{3}

6.\ this\ same\ like\ 1.\\\\x^2-196=0\\\\x^2-14^2=0\\\\(x-14)(x+14)=0\iff x=14\ \vee\ x=-14
3 0
3 years ago
- Which of the following would best be solved using completing the square?
fenix001 [56]

Answer:

C

Step-by-step explanation:

You can only complete the square with quadratic equations (equations leading with x^2)

C is the only answer choice that leads with x^2

6 0
2 years ago
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A factory manager is packing engine components into wooden crates to be shipped on a small truck. The truck is designed to hold
Lemur [1.5K]

Answer: 63lbs

Step-by-step explanation:

The truck can only hold 16crates and each crate weigh 12lbs, the total weight of the 16 crates will be 12×16= 192lbs

This shows that the truck can only contain extra load of 1200lbs - 192lbs = 1008lbs (excluding weight of crates).

To get the shipment weigh close to the total of 1200lbs, the truck must be loaded with engine components not more than 1008lbs.

Since we have 16 crates to fill with engine components not more than 1008lb, each crates will therefore must not exceed 1008/16 pounds of engine components which is equivalent to 63lbs.

Therefore, the manager should instruct the workers to put 63lbs of machine components in "each crate" in order to get the shipment weight as close as possible to 1200 lbs.

6 0
4 years ago
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