25 cents you dumb stupid child
Hello:<span>
the equation is : y = ax+b
the slope is a : a×(2/3) = -1......(
perpendicular to a line : 2x-3y =7 with a slope of 2/3 because : y = (2/3)x-7/3)
a = -3/2 y=(-3/2)x+b
the line that passes through (-2, 1) : 1 =
(-3/2)(-2)+b
b = -2
<span> the equation is : y = (-3/2)x-2</span></span>
<h3>Part 1</h3>
If we simplify, both Joe and Hope factored the polynomial correctly but Joe didn't complete it fully.
<u>The first binomial can be further factored:</u>
<h3>Part 2</h3>
The quadratic expression needs to have two roots in order to be factored as two binomials.
<u>The discriminant must be positive or zero:</u>
We have a = 3, b = k, c = -8
<u>So we get following inequality:</u>
- k² - 4*3*(-8) ≥ 0
- k² + 96 ≥ 0
<u>Since k² is positive for any value of k, the solution is any value of k:</u>
Answer:
30° , 170°
Step-by-step explanation:
Let the remaining two angles be 3x & 17x. As it is a quadrilateral , the sum of all the angles of quadrilateral is 360°. So,
Putting the value of x , remaining angles are
(3×10 = 30°) & (17×10 = 170°)
You can solve this by substitution.
x+y=10
x-y=4
===== add the equations
2x=14
x=7
Then plug in x into one of the equations
7+y=10
y=3
so x^2=7*7=49
y^2=3*3=9
Hope that helps!
