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Varvara68 [4.7K]
3 years ago
7

Pleaseeee help!!!! I will mark you as brainlinest for correct answer!!!!!

Mathematics
2 answers:
Semmy [17]3 years ago
7 0
P = 2w + 2L
Flip
2w + 2L = P
Subtract both sides by 2L
2w = P - 2L
Divide both sides by 2
w = (P - 2L) / 2

You chose the right answer choice!
Have an awesome day! :)
scZoUnD [109]3 years ago
7 0
The answer is C I love math any time you need someone to help you Im here

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In circle J with m \angle HJK= 92m∠HJK=92 and HJ=9HJ=9 units find area of sector HJK. Round to the nearest hundredth.
Diano4ka-milaya [45]

Answer:

65.03square units.

Step-by-step explanation:

Find the diagram in the attachment below.

Area of the sector HJK = theta/360° × πr²

theta is the angle subtended by the sector = ∠HJK = 92°

r is the radius = HJ = 9units.

Substituting the given values in the formula:

Area of sector HJK = 92°/360° × π(9)²

Area of sector HJK = 23,399.28/360

Area of sector HJK = 65.03 square units to nearest hundredth

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3 years ago
Every day Kim practice volleyball and clarinet each day she practices volleyball for 2.5 hours if after a days she practices bot
AlexFokin [52]

Correct question:

Every day Kim practice volleyball and clarinet each day she practices volleyball for 2.5 hours if after 8 days she practices both volleyball and the clarinet for a total of 36 hours how many hours per day did Kim practice clarinet.

Answer: 2 hours

Step-by-step explanation:

Everyday Kim practices volleyball and clarinet = v/ball + clarinet

Everyday volleyball practice = 2.5hours

That is clarinet(hours) + 2.5 hours of volleyball

After 8 day, total practice hours of both volleyball and clarinet equals 36 hours

The above information can be represented mathematically as thus:

Let h = hours per day of clarinet

8(h + 2.5) = 36

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h = 16/8

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3 years ago
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Wittaler [7]

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Function A's y-intercept would be (0, -1) and Function B's y-intercept is (0, 4). Therefore, Function A's y-intercept is less than Function B's.

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2 years ago
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Artyom0805 [142]

Answer:

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Step-by-step explanation:

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3 years ago
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