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Alexeev081 [22]
2 years ago
10

Please please please help

Mathematics
2 answers:
kondor19780726 [428]2 years ago
6 0
What's up? this answer is 6 chapters per hour. as Lamya read this in 6 hours, we divide 36 by 6 to get 6 chapters per hour

best of luck with your studies
PilotLPTM [1.2K]2 years ago
4 0
Answer:
6 chapters per hour

Step-by-step explanation:
If in 6 hours Lamya reads 36 chapters, her average reading speed is 6 chapters per hour. To get the answer, you simply divide 36(how many chapters she read) with 6 (how long it took).
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An object is launched at 29.4 meters per
Lerok [7]

Answer:

The reasonable domain for the scenario is option 'a';

a) [0, 7]  

Step-by-step explanation:

For the projectile motion of the object, we are given;

The speed at which the object is launched, v = 29.4 meters per second

The height of the platform from which the object is launched, h = 34.3 meter

The equation for the height of the object as a function of time 'x' is given as follows;

f(x) = -4.9·x² + 29.4·x + 34.3

The domain for the scenario, is given by the possible values of 'x' for the function, which is found as follows;

At the height from which the object is launched, x = 0, and f(x) = 34.3

At the ground level to which the object can drop, f(x) = 0

∴ f(x) = -4.9·x² + 29.4·x + 34.3 = 0

-4.9·x² + 29.4·x + 34.3 = 0

By the quadratic formula, we have;

x = (-29.4 ± √(29.4² - 4 × (-4.9) × 34.3))/(2 × (-4.9)

∴ x = -1, or 7

Given that time is a natural number, we have the reasonable domain for the scenario as the start time when the object is launched, t = 0 to the time the object reaches the ground, t = 7

Therefore, the reasonable domain for the scenario is; 0 ≤ x ≤ 7 or [0, 7].

4 0
3 years ago
Which word best replaces shakes in rapid motion to be more precise
Zielflug [23.3K]

Answer:

flutter, flap, beat, agitate, vibrate; tremble          could be one of these

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
I will mark your question as The Brainlest. (+40 points!)
Aleksandr [31]
Your answer would be 248 i hope this helps and please mark me as brainliest :)
8 0
3 years ago
Read 2 more answers
Find an equation for a line that is normal to the graph of y=xe^x and goes through the origin
Marina CMI [18]
Y = xe^x
dy/dx(e^x x)=>use the product rule, d/dx(u v) = v*(du)/(dx)+u*(dv)/(dx), where u = e^x and v = x:
= e^x (d/dx(x))+x (d/dx(e^x))
y' = e^x x+ e^x
y'(0) = 1 => slope of the tangent
slope of the normal = -1
y - 0 = -1(x - 0)
y = -x => normal at origin
3 0
3 years ago
Can someone help me with this please
Arisa [49]
I’ve attached my work...
Hope it helps!
Math-way app for problems like number 2
Have a nice day:)

6 0
3 years ago
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