Solve the following system of equations using substitution. What is the value of y?
2 answers:
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The discriminant is the secion inside the double parenthasees [()] below in the quadratic formulat which is
x=![\frac{-b+ \sqrt{[(b^{2}-4ac)]} }{2a}](https://tex.z-dn.net/?f=%20%5Cfrac%7B-b%2B%20%5Csqrt%7B%5B%28b%5E%7B2%7D-4ac%29%5D%7D%20%7D%7B2a%7D%20)
the determinant determines or tells whether the answer is real or imaginary
if it is negative, then it is imaginary, if positive, then it is real
so basically the discriminmant is
so ax^2+bx+c
a=x^2-2x-15
a=1
b=-2
c=-15
subsitute
=4-4(1)(-15)=4+60=64
the discriminant is () or 64
x=
the determinant determines or tells whether the answer is real or imaginary
if it is negative, then it is imaginary, if positive, then it is real
so basically the discriminmant is
so ax^2+bx+c
a=x^2-2x-15
a=1
b=-2
c=-15
subsitute
the discriminant is (