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spayn [35]
3 years ago
12

Help with this question !

Mathematics
1 answer:
Genrish500 [490]3 years ago
5 0
Statements                                           Reasons
1. Write all the given as you did            1. Given
2. <DBA and <DBC are right angles     2. Def of perpendicular lines
3. m<DBA = 90                                     3. Def of right angle
    m<DBC = 90
4. m<DBA = m<DBC                             4. Substitution
5. m<DBA = m<1 + m<3                       5. Angle addition postulate
    m<DBC = m<2 + m<4
6. m<1 + m<3 = m<2 + m<4                  6. Substitution
7. m<3 = m<4                                        7. Subtraction prop of equality
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If x=0 and x=3 then 3 divided by 2x to the second power minus 2 divided by x to the second power minus 3x
Afina-wow [57]
Answer: undefined in both cases.


Explanation:

1) Expression to evaluate:

\frac{3}{2x^2} - \frac{2}{x^2-3x}

2) You are asked to evaluate that expression for two different cases, x = 0 and x = 3.

3) First case: x = 0

The expression cannot be evaluated at x = 0, because the denominators (both  denominators) equal 0, and the division by 0 is not defined.

So, the answer is undefined.

4) Second case, x = 3

When you replace x = 3 you get:

\frac{3}{2x^2} - \frac{2}{x^2-3x} = \frac{3}{2(3^2)} - \frac{2}{3^2-3(3)} = \frac{3}{18} - \frac{2}{9-9}

Again, this result in a division by 0, so you conclude that it is undefined too.

8 0
2 years ago
What has a sum of 100 and a difference of 80 help me please
irga5000 [103]

Answer:

90 and 10

Step-by-step explanation:

90 + 10 = 100

90 - 10 = 80

6 0
3 years ago
The length of a rectangle is 3ft more than twice the width, and the area of the rectangle is 54ft^2. Find the dimensions of the
777dan777 [17]

Answer: Let length = 2x + 3

Let width = x

Area = 54 ft2

length × width = Area

x(2x + 3) = 54

2x2 + 3x = 54

2x2 + 3x - 54 = 0

(2x - 9)(x + 6) = 0

x = 9/2 and x = -6

x = 4.5 and x = -6

We accept x = 4.5 because length cannot be a negative value. Substituting this value into the dimensions:

width = 4.5 ft

length = 2(4.5) + 3 = 9 + 3 = 12 ft

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Elasticity of Demand The demand function for a certain brand of backpacks is
Trava [24]

Answer:

See explanation

Step-by-step explanation:

Solution:-

- The demand function of a certain brand is given as price P a function of x quantity of goods ( in hundred ) demanded per month. The relation is:

                           P ( x ) = 50 Ln ( 50 / x ).

- The point price elasticity ( E ) of demand is given by:

                           E = \frac{P}{x}*\frac{dP}{dx}  

- Where, dP / dx : is the rate of change of price ( P ) with each hundred unit of good ( x ) is demanded.

- To determine the " dP / dx " by taking the first derivative of the given relation:

                          P ( x ) = 50 Ln ( 50 / x ).

                          d P ( x ) / dx = [ 50*x / 50 ] * [ -1*50 / x^2 ]

                                              = - 50 / x

- Hence the point price elasticity of demand is given by:

                          E = - ( P / x ) * ( 50 / x )

                          E = -50*P / x^2    

- For an inelastic demand, ! E ! is < 1:

                          ! -50*P / x^2 ! < 1

                          50*P / x^2 < 1

                          P < x^2 / 50

- For an unitary demand, ! E ! is =  1:

                          ! -50*P / x^2 !  = 1

                          50*P / x^2 = 1

                          P = x^2 / 50

- For an inelastic demand, ! E ! is > 1:

                          ! -50*P / x^2 ! > 1

                          50*P / x^2 > 1

                          P > x^2 / 50

2)

If the unit price is increased slightly from $50, will the revenue increase or decrease?

- We see from the calculated demand sensitivity d P / dt:

                          d P ( x ) / dx = - 50 / x

- We see that as P increases the from P = $50, the quantity of goods demanded would be:

                          50 = 50 ln(50/x)

                           1 = Ln ( 50 / x )

                           50/x = e

                           x = 50 / e

Then,

                          d P ( x ) / dx = - 50 / ( 50 / e )

                          d P ( x ) / dx = - e

- We see that if price slightly increases from $ 50 then the quantity demanded would decrease by e (hundreds ) goods.

- The decrease in the quantity demanded is higher than the increase in price. The revenue is given by the product of price P ( x ) and x:

                Revenue R ( x ) = P ( x ) * x

                                = 50*x*ln(50/x)

Then the product of price and quantity goods also decreases; hence, revenue decreases.

8 0
3 years ago
Will got 16 out of 20 correct. If he continues at the same rate, how many questions would he get correct out of 75?
nevsk [136]

Answer:

60

Step-by-step explanation:

16/20 times 75

5 0
3 years ago
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