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4 years ago

Try not to park next to ____ or vechicles that are too close to the white space markings.

Mathematics

1 answer:

Anestetic [448]4 years ago

8 0

3 probably it makes the most sense if you ask me

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HELP A SHAWTY PLZ its math....

alekssr [168]

Answer:

3 faces

Step-by-step explanation:

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3 years ago

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98-12+e <br> =106<br> Need help quick

Serjik [45]

Answer:

$98 - 12 + e = 106 \\ 86 + e = 106 \\ e = 10 6 - 86 \\ e = 20$

ʜᴏᴘᴇ ɪᴛ ʜᴇʟᴘs ʏᴏᴜ.

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3 years ago

Match each three dimensional figure to its volume based on the given dimensions.

Gre4nikov [31]

please attach a diagram

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3 years ago

Two partners agree to invest equal amounts in their business. One will contribute $10,000 immediately. The other plans to contr

krek1111 [17]

Answer:

She should contribute $ 8369.38 ( approx )

Step-by-step explanation:

Let P be the amount invested by the other partner,

∵ The amount formula in compound interest,

$A=P(1+\frac{r}{n})^{nt}$

Where,

r = annual rate,

n = number of compounding periods in a year,

t = number of years,

Here, r = 9% = 0.09, n = 4 ( quarters in a year ), t = 2 years,

Then the amount after 2 years,

$A = P(1+\frac{0.09}{4})^{8}$

According to the question,

A = $ 10,000,

$P(1+\frac{0.09}{4})^{8}= 10000$

$P(1+0.0225)^8 = 10000$

$\implies P = \frac{10000}{1.0225^8}\approx \$ 8369.38$

6 0

3 years ago

1)a chord of length 18cm midway the radius of a circle. calculate the radius of the circle correct to 1d.p. 2)if two parallel ch

kykrilka [37]

Part 1:

Given that the length of the chord is 18 cm and the chord is midway the radius of the circle.

Thus, half the angle formed by the chord at the centre of the circle is given by:

$\cos\theta=\frac{\left( \frac{1}{2} r\right)}{r}= \frac{1}{2} \\ \\ \Rightarrow\theta=\cos^{-1}\left( \frac{1}{2} \right)=60^o$

Now,

$\sin60^o= \frac{9}{r} \\ \\ \Rightarrow r= \frac{9}{\sin60^o} =10.392$

Therefore, the radius of the circle is 10.4 cm to 1 d.p.

Part 2I:

Given that the radius of the circle is 10 cm and the length of chord AB is 8 cm. Thus, half the length of the chord is 4cm. Let the distance of the mid-point O to /AB/ be x and half the angle formed by the chord at the centre of the circle be θ, then

$\sin\theta= \frac{4}{10} = \frac{2}{5} \\ \\ \theta=\sin^{-1}\left( \frac{2}{5} \right)=23.6^o$

Now,

$\cos23.6^o= \frac{x}{10} \\ \\ \Rightarrow x=10\cos23.6^o=9.165\approx9.2cm$

Part 2II:

Given that the radius of the circle is 10cm and the angle distended is 80 degrees. Let half the length of chord CD be y, then:

$\sin40^o= \frac{y}{10} \\ \\ \\ \Rightarrow y=10\sin40^o=6.428$

Thus, the length of chord CD = 2(6.428) = 12.856 which is approximately 12.9 cm.

3 0

3 years ago