Given that the total area of the walkway and the pool is w²+17w+66, and the width w, will be found as follows:
A=length×width
A=w²+17w+66
to get the new width we need to factorize the above quadratic form
A=w²+17w+66
=w²+11w+6w+66
=w(w+11)+6(w+11)
=(w+11)(w+6)
From the answer, the width=6 units, length=11 units
Answer: JL = 25
Step-by-step explanation: Segment JM is the total measure of the line segment and it equals 45.
Suppose first segment JK measures d.
The total ratio is the sum of each part
d + 4d + 4d = 9d
The sum of each part corresponds to the total measure of the line segment. Then:
9d = 45
d = 5
Segment JL is
JL = d + 4d
JL = 5d
JL = 5.5
JL = 25
Segment JL measures 25 units.
Since the exponent is negative, you move the decimal (2.0) to the left two spots leaving you with .02
The average slope (s) on the interval [a, b] is given by
s = (f(b) -f(a))/(b -a)
When there are a lot of computations to do, it is convenient to let a machine do them. The intervals and slopes are ...
[0, 5] : 5
[-3, 3] : 0
[-5, 3] : -2
[-3, 5] : 2