Answer:
99.99499987
Step-by-step explanation:
Here is
the solution for this specific problem:
<span>Based from the graph,
the curve will intersect itself at the y-axis, i.e. x = 0. </span><span>
</span><span>t^3 - 6t = 0 </span><span>
<span>t(t^2 -
6) = 0 </span>
<span>t = 0 or
t = ± √6 </span>
<span>dx/dt =
3t^2 - 6 </span>
<span>dy/dt =
2t </span>
<span>dy/dx =
2t/(3t^2 - 6) </span>
<span>@ t = 0,
dy/dx = 0. </span>
<span>x = 0, y
= 0 </span>
<span>y = 0 </span>
<span>@ t = √6,
dy/dx = 2√6/12 = √6/6 </span>
<span>x = 0, y
= 6 </span>
<span>y - 6 =
(√6/6) x </span>
<span>y =
(√6/6)x + 6 </span>
<span>@ t =
-√6, dy/dx = -2√6/12 = -√6/6 </span>
<span>x = 0, y
= 6 </span>
<span>y - 6 =
(-√6/6) x </span>
y = (-√6/6)x
+ 6</span>
So the equations of the tangent
line at the point where the curve crosses itself are: <span>y = (√6/6)x + 6 and
</span>y = (-√6/6)x + 6. I am hoping that these answers have
satisfied your queries and it will be able to help you in your endeavors, and
if you would like, feel free to ask another question.
Answer:
a:h=square root of 0.6
Step-by-step explanation:
thank you for your time today
