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3 years ago

Find the product of 2x2(x + 6). 8x3 2x3 + 12x2 3x3 + 12x2 2x2 + x + 6

Mathematics

2 answers:

creativ13 [48]3 years ago

6 0

Answer:

I think the answer is D

Step-by-step explanation:

Verizon [17]3 years ago

5 0

The proper answer to this question would be 2

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Help if possible.

skelet666 [1.2K]

A ) Length = 5 - 2 x
Width = 3 - 2 x
The area of the bottom:
A = L x W = ( 5 - 2 x ) ( 3 - 2 x ) = 15 - 10 x - 6 x + 4 x² =
= 4 x² - 16 x + 15
b ) 4 x² - 16 x + 15 = 10
4 x² - 16 x + 5 = 0
x = (16 - √(256 - 80))/ 8 = ( 16 - 13.266 ) / 2
x = 0.34 in

4 0

3 years ago

PQRS is a parralelogram. the position vector of Q R and S are 5i +7j, -3i-8j and -4i-6j. find the position vector of P

g100num [7]

The value of the variable x = 6 and y = 5. Then the position vector of P will be 6i + 5j.

<h3>What is the equation of a line passing through two points?</h3>

The equation of line is given as

y = mx + c

Where m is the slope and c is the y-intercept.

PQRS is a parallelogram. the position vector of Q R and S are 5i +7j, -3i-8j and -4i-6j.

Then the point of Q, R, and S will be (5, 7), (-3, -8), and (-4, -6).

Let the point P be (x, y).

We know that the slope of the line QS and PQ will be same and line is passing through (-3, -8).

y = 1.444x + C

-8 = 1.444 (-3) + C

C = -3.667

Then the equation will be

y = 1.444x – 3.667 …1

The slope of the line PQ and RS will be same and line is passing through (5, 7).

y = -2x + D

7 = -2 (5) + D

D = 17

Then the equation will be

y = -2x + 17 …2

By solving equation 1 and 2, we have

x = 6 and y = 5

Then the position vector of P will be

⇒ 6i + 5j

The graph is given below.

Learn more about straight-line equations here:

brainly.com/question/380976

#SPJ1

6 0

2 years ago

45612.21μ (1x10^-6 / 1μ) = ??

Oliga [24]

First let's do parentheses. 1*10^-6 = .000001. Now divide that by one it equals the same thing. Now you need to multiply that by 45612.21. That equals 0.04561221μ

8 0

4 years ago

One number is 27 less than twice another. Their sum is 93. What are the numbers?

swat32

Thirty three because I'm just smart like that so you should believe me entirely.

5 0

3 years ago

a spherical balloon is deflated at a rate of 256pi/3 cm^3/sec. at what rate is the radius of the balloon changing when the radiu

Hunter-Best [27]

What you need to look for is $\frac { dr }{ dt }$ when r=8.

Now:

$Volume\quad of\quad a\quad sphere:\\ \\ V=\frac { 4 }{ 3 } \pi { r }^{ 3 }$

$\therefore \quad \frac { dV }{ dr } =\frac { 4 }{ 3 } \pi \cdot 3{ r }^{ 2 }=4\pi { r }^{ 2 }\\ \\ \therefore \quad \frac { dr }{ dV } =\frac { 1 }{ \frac { dV }{ dr } } =\frac { 1 }{ 4\pi { r }^{ 2 } }$

$And:\\ \\ \frac { dV }{ dt } =-\frac { 256\pi }{ 3 } \\ \\ Therefore:\\ \\ \frac { dr }{ dt } =\frac { dr }{ dV } \cdot \frac { dV }{ dt }$

$\\ \\ =\frac { 1 }{ 4\pi { r }^{ 2 } } \cdot -\frac { 256\pi }{ 3 } \\ \\ =-\frac { 256 }{ 12 } \cdot \frac { \pi }{ \pi } \cdot \frac { 1 }{ { r }^{ 2 } }$

$\\ \\ =-\frac { 64 }{ 3{ r }^{ 2 } } \\ \\ When\quad r=8,\\ \\ \frac { dr }{ dt } =-\frac { 64 }{ 3\cdot { 8 }^{ 2 } } =-\frac { 1 }{ 3 } \\ \\ Answer:\quad -\frac { 1 }{ 3 } \quad cm/sec$

3 0

4 years ago