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4 years ago

Which value of x satisfies the equation |-2x|=10

Mathematics

1 answer:

uranmaximum [27]4 years ago

5 0

Answer:

Step-by-step explanation:

First you will divide I-2xI on both sides that should look like this:

-2x/-2 = 10/-2

when you divide it your -2‘s should cancel out and you should be left with

-x=10/-2

when You divide 10/-2 you should get -5

10/-2= -5

your answer should look like this then

-x=-5

-5 is just one of your answers the other is 5

To get rid of the negative on the -X you have to didvide it by both sides

-x/-x=-5/-x

your answer should be

X= 5

your final answers are

-5 or 5

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This means X = 104 - 61.

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4 years ago

Find the experimental probability that the first three students to arrive at school are boys

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Step-by-step explanation:

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4 years ago

g European roulette. The game of European roulette involves spinning a wheel with 37 slots: 18 red, 18 black, and 1 green. A bal

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Answer:

The expected value and standard deviation of your total winnings are -$0.081 and $3 respectively.

Step-by-step explanation:

We are given that the game of European roulette involves spinning a wheel with 37 slots: 18 red, 18 black, and 1 green.

Gamblers can place bets on red or black. If the ball lands on their color, they double their money. If it lands on another color, they lose their money.

Let the probability of the ball landing on red slot = $\frac{18}{37}$

The probability of the ball landing on black slot = $\frac{18}{37}$

The probability of the ball landing on green slot = $\frac{1}{37}$

Now, it is stated that Gambler can place bets only on the red or black slot, so;

The probability of winning the bet will be = $\frac{18}{37}$

and the probability of losing the bet will be = $\frac{18}{37}+\frac{1}{37}$

= $\frac{19}{37}$

If the gambler wins he gets $3 and if he loses he will get -$3.

So, the expected value of gambler's total winnings is given by;

E(X) = $\sum X \times P(X)$

= $\$3 \times \frac{18}{37} + (-\$3 \times \frac{19}{37})$

= $\$3 \times (-\frac{1}{37})$ = -$0.081

Now, the standard deviation of gambler's total winnings is given by;

S.D.(X) = $\sqrt{(\sum X^{2} \times P(X))-(\sum X \times P(X))^{2} }$

So, $E(X^{2})=\sum X^{2} \times P(X)$

= $\$3^{2} \times \frac{18}{37} + (-\$3^{2} \times \frac{19}{37})$

= $\$9 \times (\frac{18}{37}+\frac{19}{37})$ = $9

Now, S.D.(X) = $\sqrt{\$9-(-\$0.081)^{2} }$

= $\sqrt{8.993}$ = $2.99 ≈ $3

Hence, the expected value and standard deviation of your total winnings are -$0.081 and $3 respectively.

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3 years ago

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4 years ago

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