The <em>speed</em> intervals such that the mileage of the vehicle described is 20 miles per gallon or less are: v ∈ [10 mi/h, 20 mi/h] ∪ [50 mi/h, 75 mi/h]
<h3>How to determine the range of speed associate to desired gas mileages</h3>
In this question we have a <em>quadratic</em> function of the <em>gas</em> mileage (g), in miles per gallon, in terms of the <em>vehicle</em> speed (v), in miles per hour. Based on the information given in the statement we must solve for v the following <em>quadratic</em> function:
g = 10 + 0.7 · v - 0.01 · v² (1)
An effective approach consists in using a <em>graphing</em> tool, in which a <em>horizontal</em> line (g = 20) is applied on the <em>maximum desired</em> mileage such that we can determine the <em>speed</em> intervals. The <em>speed</em> intervals such that the mileage of the vehicle is 20 miles per gallon or less are: v ∈ [10 mi/h, 20 mi/h] ∪ [50 mi/h, 75 mi/h].
To learn more on quadratic functions: brainly.com/question/5975436
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All of the angles should be the same because a square has all equal angles and side lengths.
Answer:
379.56 ft
Step-by-step explanation:
25 squared = 625
diameter of the half circle is 25
Diameter divided by 2 is radius
pi r squared is the formula for area of circle
r=12.5
pi * 12.5 squared
Under Daily flat rate, we would have 22 and 0.15x
Under Cost per mile, we would have 0.15
Under Number of Miles Driven, we would have x
The correct answer I got was 22 cups. 11/2 ÷ 1/4 is how you set it up. Then, you do KCF which stands for keep, change, flip. So, your new expression is 11/2 × 4/1. You cross reduce 4 & 2 which makes the new expression 11/1 × 2/1. 11 times 2 is 22/1 which still equals 22.